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vodka [1.7K]
3 years ago
6

Simplify 7^8x7^3x7^4/7^9x7^5

Mathematics
2 answers:
KiRa [710]3 years ago
6 0

Please take a photo of this problem... it looks very hard when it is written in the way you did.

<h3>If I am reading this correctly the answer should be 1,977,326,743x^3</h3>

love history [14]3 years ago
5 0

Answer:

7^29

Step-by-step explanation:

7^8 x 7^3 x 7^4 x 7^9 x 7~5

= 7^29

= 3.21991 x 10^24

Hoped I helped

mark me as brainliest

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Highest common factor of 92 and 42
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To get the Greates Common Factor (GCF) of 92 and 42 we need to factor each value first and then we choose all the copies of factors and multiply them: 

<span><span>92:   22  23</span><span>42:   2 37 </span><span>GCF:   2    </span></span>

The Greates Common Factor (GCF) is:   2

 

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Which expression is equivalent to -36 - 8−36, 36, minus, 8? Choose 1 answer: Choose 1 answer: (Choice A) A -36+(-8)−36+(−8)minus
nordsb [41]

Answer:

Choice A: -36 + (-8)

Step-by-step explanation:

We want to find the equivalent expression to -36 - 8

The correct option is Choice A.

Choice A is -36 + (-8)

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8 0
3 years ago
25 Points ! Write a paragraph proof.<br> Given: ∠T and ∠V are right angles.<br> Prove: ∆TUW ∆VWU
vladimir2022 [97]

Answer:

Δ TUW ≅ ΔVWU ⇒ by AAS case

Step-by-step explanation:

* Lets revise the cases of congruent for triangles

- SSS  ⇒ 3 sides in the 1st Δ ≅ 3 sides in the 2nd Δ

- SAS ⇒ 2 sides and including angle in the 1st Δ ≅ 2 sides and  

 including angle in the 2nd Δ  

- ASA ⇒ 2 angles and the side whose joining them in the 1st Δ  

 ≅ 2 angles and the side whose joining them in the 2nd Δ  

- AAS ⇒ 2 angles and one side in the first triangle ≅ 2 angles

 and one side in the 2ndΔ

- HL ⇒ hypotenuse leg of the first right angle triangle ≅ hypotenuse

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* Lets solve the problem

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- ∠T and ∠V are right angles

- LINE TW is parallel to line VU

∵ TW // VU and UW is a transversal

∴ m∠VUW = m∠TWU ⇒ alternate angles (Z shape)

- Now we have in the two triangles two pairs of angle equal each

 other and one common side, so we can use the case AAS

- In Δ TUW and ΔVWU

∵ m∠T = m∠V ⇒ given (right angles)

∵ m∠TWU = m∠VUW ⇒ proved

∵ UW = WU ⇒ (common side in the 2 Δ)

∴ Δ TUW ≅ ΔVWU ⇒ by AAS case

7 0
3 years ago
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Answer: First option.

Step-by-step explanation:

You know that the product obtained by multiplying a binomial and a trinomial is:

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Then, in order to simplify this product, it is necessary to add the like terms.

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You can  observe that this matches with the first option.

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3 years ago
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