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3 years ago

14

The temperature is changing every day by negative 3 over 16 degrees Fahrenheit. What will be the change in the temperature after

4 days?

1 answer:

aliya0001 [1]3 years ago

5 0

Answer:

"The temperature would be $-\frac{3}{4}$ changed"

Step-by-step explanation:

Temperature is changing by $-\frac{3}{16}$ degrees F per day

So in 4 days, it will change:

$4*(-\frac{3}{16})\\=-\frac{3}{4}$ degrees Fahrenheit

Hence, the temperature after 4 days would be 3/4th degree Fahrenheit lower.

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Find the perimeter AND area of the parallelogram ABCD. Show all work

nexus9112 [7]

Since, this is parallelogram

so, opposite sides are equal

We will find value of sides

Calculation of AB:

we are given point A=(-2,3)

point B=(4,0)

we can use distance formula

$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

now, we can plug values

$AB=\sqrt{(4+2)^2+(3-0)^2}$

$AB=3\sqrt{5}$

Since, this is parallelogram

so, opposite sides are equal

so,

$CD=AB=3\sqrt{5}$

Calculation of AD:

point A =(-2,3)

point D=(-5,2)

we can use distance formula

$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

now, we can plug values

$AD=\sqrt{(-5+2)^2+(2-3)^2}$

$AD=\sqrt{10}$

Since, this is parallelogram

so, opposite sides are equal

so,

$BC=AD=\sqrt{10}$

Calculation of AE:

point A=(-2,3)

point E=(-3,1)

we can use distance formula

$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

now, we can plug values

$AE=\sqrt{(-3+2)^2+(1-3)^2}$

$AE=\sqrt{5}$

(a)

we know that

perimeter of a parallelogram is sum of all sides

so,

perimeter is

$=AB+BC+CD+DA$

now, we can plug values

$=3\sqrt{5}+\sqrt{10}+3\sqrt{5}+\sqrt{10}$

$=6\sqrt{5}+2\sqrt{10}$ ...........Answer

(b)

we can use area of parallelogram formula

$A=AE\times CD$

we can plug values

$A=\sqrt{5}\times 3\sqrt{5}$

$A=15$ ............Answer

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Answer:

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$m\angle x=67^o$ ----> by alternate exterior angles

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dlinn [17]

Step-by-step explanation:

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the answer to the question

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professor190 [17]

Answer:

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Answer:

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3 years ago