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3 years ago

5

Help me plz one this

2 answers:

german3 years ago

5 0

Answer:

theee answer is 0.0028

Keith_Richards [23]3 years ago

4 0

Answer:

0.0028

Step-by-step explanation:

You might be interested in

Evaluate 4x-7 when x=5

Anna007 [38]

The answer is 13.

You can evaluate this by substituting x for 5 in the expression.

4x-7
4(5)-7
20-7
13

4 0

4 years ago

Read 2 more answers

Micheal has saved 22.40 cents Kevin saved 3/4 of the amount that micheal saved. Jack saved 5 times as much as kevin. What is the

JulijaS [17]

Answer:

$151.20

Step-by-step explanation:

(22.40x0.75)+(22.40x5)+22.40=151.20

8 0

3 years ago

A sheet of paper 90 cm-by-66 cm is made into an open box (i.e. there's no top), by cutting x-cm squares out of each corner and f

NNADVOKAT [17]

Answer:

$26 - \sqrt{181}$ cm

Step-by-step explanation:

The volume of the box is:

V = height * length * width

V = x*(66 - 2*x)*(90 - 2*x)

V = (66*x - 2*x^2)*(90 - 2*x)

V = 5940*x - 132*x^2 - 180*x^2 + 4*x^3

V = 4*x^3 - 312*x^2 + 5940*x

where x is the length of the sides of the squares, in cm.

The mathematical problem is :

Maximize: V = 4*x^3 - 312*x^2 + 5940*x

subject to:

x > 0

2*x < 66 <=> x < 33

In the maximum, the first derivative of V, dV/dx, is equal to zero

dV/dx = 12*x^2 - 624*x + 5940

From quadratic formula

$x = \frac{-b \pm \sqrt{b^2 - 4(a)(c)}}{2(a)}$

$x = \frac{624 \pm \sqrt{(-624)^2 - 4(12)(5940)}}{2(12)}$

$x = \frac{624 \pm \sqrt{104256}}{24}$

$x = \frac{624 \pm \sqrt{2^6*3^2*181}}{24}$

$x = \frac{624 \pm 8*3*\sqrt{181}}{24}$

$x_1 = \frac{624 + 24*\sqrt{181}}{24}$

$x_1 = 26 + \sqrt{181}$

$x_2 = \frac{624 - 24*\sqrt{181}}{24}$

$x_2 = 26 - \sqrt{181}$

But $x_1 > 33$ , then is not the correct answer.

5 0

3 years ago

Simplify. 2+35x−1−15x 1+25x 3−45x 1−25x 3+25x

Lelu [443]

Answer:

Option A is correct.

$1+\frac{2}{5}x$

Step-by-step explanation:

Simplify: $2+\frac{3}{5}x - 1 -\frac{1}{5}x$ ......[1]

Like terms are those terms who have same variable to the same power.

Combine like terms in [1] ,we have;

$1+(\frac{3}{5}x- \frac{1}{5}x)$

Simplify:

$1+\frac{2}{5}x$

Therefore, the simplified form of $2+\frac{3}{5}x - 1 -\frac{1}{5}x$ is, $1+\frac{2}{5}x$

3 0

3 years ago

Read 2 more answers

HELP TIMER Write the equation of a hyperbola centered at the origin with x-intercept +/- 4 and foci of +/-2(squareroot 5)

meriva

Given:

x-intercepts of the hyperbola are ±4.

The foci of hyperbola are $\pm 2\sqrt{5}$ .

Center of the hyperbola is at origin.

To find:

The equation of the hyperbola.

Solution:

The general equation of a hyperbola:

$\dfrac{(x-h)^2}{a^2}-\dfrac{(y-k)^2}{b^2}=1$ ...(i)

Where, (h,k) is the center of the hyperbola, ±a are x-intercepts, $(\pm c,0)$ are foci.

Center of the hyperbola is at origin. So, h=0 and k=0.

x-intercepts of the hyperbola are ±4. So,

$\pm a=\pm 4$

$a=4$

The foci of hyperbola are $\pm 2\sqrt{5}$ .

$\pm c=\pm 2\sqrt{5}$

$c=2\sqrt{5}$

We know that,

$a^2+b^2=c^2$

$(4)^2+b^2=(2\sqrt{5})^2$

$16+b^2=20$

$b^2=20-16$

$b^2=4$

Taking square root on both sides, we get

$b=\sqrt{4}$ [b>0]

$b=2$

Substituting $h=0,k=0,a=4,b=2$ in (i), we get

$\dfrac{(x-0)^2}{4^2}-\dfrac{(y-0)^2}{2^2}=1$

$\dfrac{x^2}{4^2}-\dfrac{y^2}{2^2}=1$

Therefore, the correct option is (d).

4 0

3 years ago