If ΔABC≅ΔDEF, then what corresponding parts are congruent?
1 answer:
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Answer:
<em>Answer: Quadrant 4</em>
Step-by-step explanation:
<u>Graph of Functions </u>
Let's analyze the function
To better understand the following analysis, we'll factor y
For y to have points in the first quadrant, at least one positive value of x must produce one positive value of y. It's evident that any x greater than 0 will do. For example, x=1 will make y to be positive in the numerator and in the denominator, so it's positive
For y to have points in the second quadrant, at least one negative value of x must produce one positive value of y. We need two of the factors that are negative. It can be seen that x=-2 will make y as positive, going through the second quadrant.
For the third quadrant, we have to find at least one value of x who produces a negative value of y. We only need to pick a value of x that makes one or all the factors be negative. For example, x=-4 produces a negative value of y, so it goes through the third quadrant
Finally, the fourth quadrant is never reached by any branch because no positive value of x can produce a negative value of y.
Answer: Quadrant 4
The solution of the linear equations will be ( -2, 4).
<h3>What is an equation?</h3>It is defined as the relation between two variables, if we plot the graph of the linear equation we will get a straight line.
Given equations are:-
- 2x +3y = 8 and 3x+y= -2
Solving the equations by elimination method:-
2x +3y = 8
3x+y= -2
Multiply the second equation by 3 and subtract from the first equation.
2x +3y = 8
-9x -3y = 6
----------------
-7x = 14
x = -2
Out of the value of x in any one equation, we will get the value of y.
3x+y= -2
3 ( -2) + y = -2
-6 + y = -2
y = 4
The graph of the equations is also attached with the answer below.
Therefore the solution of the linear equations will be ( -2, 4).
The complete question is given below:-
Exploring Systems of Linear Equations 2x +3y =8 and 3x+y= -2. Find the value of x and y and draw a graph for the system of linear equations.
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