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mamaluj [8]
3 years ago
8

If ΔABC≅ΔDEF, then what corresponding parts are congruent?

Mathematics
1 answer:
Virty [35]3 years ago
7 0
All angles are congruent to its corresponding part. While all segments are similar to its corresponding part
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Describe possible dimensions of a pyramid with a volume of 30 cubic centimeters.
Contact [7]

Answer:

15*3*2

15*1*6

45*2*1

10*3*3

6*5*3

Step-by-step explanation:

Volume=Lenth *Width*Height divieded by 3

4 0
3 years ago
Read 2 more answers
Prove the identity<br> cos(A+B+C)=cosAcosBcosC-cosAsinBsinC-sinAcosBcosC-sinAsinBcosC
blagie [28]
Hello !

cos (a+b) = cos a cos b - sin a sin b
sin (a+b) = sin a cos b + sin b cos a

cos (a+b+c) = cos (a+(b+c))
cos (a+b+c) = cos a cos (b+c) - sin a sin (b+c)
cos (a+b+c) = cos a (cos b cos c - sin b sin c) - sin a (sin b cos c + sin c cos b)
cos (a+b+c)=cos a cos b cos c - cos a sin b sin c - sin a sin b cos c - sin a cos b sin c
4 0
3 years ago
A sign standing 6 feet tall is situated 18 feet away from a flag pole. at a certain time of day the sign's shadow is 3 feet long
alexdok [17]
Observe attached picture.

On picture we have:
A = height of flagpole = x ft
B = length of flagpole's shadow = 24 ft
C = height of sign = 6 ft
D = length of sign's shadow = 3 ft

When we draw a picture representing this problem we can also add another line marked in red. This way we can see that we have two right-angle triangles. We can see that both have same angle marked with α.

We can apply trigonometry rules to find height of flagpole.

From small triangle containing sign we can find tangens function:
tan \alpha = \frac{C}{D}
Similarly we can do for large triangle containing flagpole:
tan \alpha = \frac{A}{B}

We see that these two equations have same left sides. This means that their right sides must also be same:
\frac{C}{D} = \frac{A}{B}
We can solve for A:
CB=AD \\ A= \frac{CB}{D}  \\ A= \frac{6*24}{3}  \\ A=48 ft

Height of flagpole is 48 feet.

8 0
4 years ago
There are 3 boys to every 5 girls in mrs. kennedy's class. if there are 40 students in the class, how many of those students are
Gala2k [10]

Ratio of girls to boys = 5/3

Number of girls in 40 students would be 3/5 * 40 = 24

4 0
3 years ago
Divide 4,318 by 7 then estimate it
11111nata11111 [884]

Answer:

4,318÷7= 617

I have already rounded the decimal to make it into a whole.

5 0
3 years ago
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