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Sonja [21]
3 years ago
15

Jenny bakes 10 cookies. She puts 7 chocolate chips on each cookie. Draw a tape diagram, and label the total amount of chocolate

chips as c. Write an equation, and solve for c.
Mathematics
1 answer:
IgorC [24]3 years ago
3 0
Jenny bakes 10 cookies. she puts 7 chocolate chips on each cookie draw a tape diagram and label the total amount
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What us the solution to the inequality 4-2 (x+10) >12
Aloiza [94]
Answer is 6/4 your welcome bro
3 0
3 years ago
Given f(x) = the quantity of 3x minus 1, divided by 2 , solve for f−1(4)
hichkok12 [17]
<span>f(x)=(<span><span>3x−1)/</span>2<----Starter </span></span>
y = (3x-1)/2
switch x and y
x = (3y-1)/2
2x = 3y-1
2x+1 =3y
y = 2/3*x + 1/3 
f^(-1) (x) = 2/3*x + 1/3 
f^(-1) (4) = 2/3*4 + 1/3 = 8/3 + 1/3 = 9/3 = 3

I hope this helps. ;)
3 0
3 years ago
Read 2 more answers
What is the slope of a line perpendicular to the line passing through E(-1,6) and F(-2,-10)?
STatiana [176]

Answer:

Step-by-step explanation:

E(-1,6)  & F(-2,-10)

Slope = \frac{y_{2}-y_{1}}{x_{2}-x_{1}}\\\\\  \  \ \ = \frac{-10-6}{-2-[-1]}\\

=\frac{-10-6}{-2+1}\\\\=\frac{-16}{-1}\\\\= 16

Slope of the line perpendicular to this line = -1/m =  -1/16

7 0
2 years ago
The point given is on the terminal side of an angle theta. Find the exact values of the six trig functions of theta.. (-3,2)
Dima020 [189]
We can use SOH, CAH and TOA, but first we must find the length of a hypotenuse:
h =\sqrt{(-3) ^{2}+2^{2} } =  \sqrt{9+4}= \sqrt{13}
sin (theta)= 2/√13
cos ( theta) = -3/√13
tan (theta) = -2/3
cot (theta ) = -3/2
sec (theta) = 1/cos(theta ) = -√13/3
csc(theta ) = 1/ sin (theta) = √13/2 
7 0
3 years ago
Please tell me the correct answer. No link will be acceptable
Nataly [62]

Answer:

The first answer: 5bk + 5b + k

Step-by-step explanation:

Now, you might say it would be the 10bk one, but that's not right.

The only you can get two variables together is through multiplication. That's why 10bk would not work.

8 0
3 years ago
Read 2 more answers
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