Quadrilateral ABCD is inscribed in this circle.
2 answers:
By the Inscribed Quadrilateral Theorem, a quadrilateral can only be inscribed if and only if opposite angles are supplementary. This means that 
are supplementary, or add up to 180°. This gives us the equation
(3<em>x</em> + 9)° + (2<em>x</em> - 4)° = 180°
Combine like terms:
5<em>x</em> + 5 = 180
Subtract 5 from each side:
5<em>x</em> + 5 - 5 = 180 - 5
5<em>x</em> = 175
Divide both sides by 5:
5<em>x</em>/5 = 175/5
<em>x</em> = 35
This means that
We take these 3 angles away from 360 and we will have the measure of angle C:
360 - 114 - 66 - 73 = 107°<em />
(3<em>x</em> + 9)° + (2<em>x</em> - 4)° = 180°
Combine like terms:
5<em>x</em> + 5 = 180
Subtract 5 from each side:
5<em>x</em> + 5 - 5 = 180 - 5
5<em>x</em> = 175
Divide both sides by 5:
5<em>x</em>/5 = 175/5
<em>x</em> = 35
This means that
We take these 3 angles away from 360 and we will have the measure of angle C:
360 - 114 - 66 - 73 = 107°<em />
You might be interested in
When it hits the ground, then h=0
find the xintercept or in this case the tintercepts
c=76
v=135
h=-16t^2+135t+76
use quadratic formula
ax^2+bx+c=0
x=
a=-16
b=135
c=76
x=
x=
x=
aprox
x=-0.5297 or 8.967
exclude the negative root since you can't have negative time
means that it takes 8.97 seconds to hit the ground
find the xintercept or in this case the tintercepts
c=76
v=135
h=-16t^2+135t+76
use quadratic formula
ax^2+bx+c=0
x=
a=-16
b=135
c=76
x=
x=
x=
aprox
x=-0.5297 or 8.967
exclude the negative root since you can't have negative time
means that it takes 8.97 seconds to hit the ground