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atroni [7]
3 years ago
9

Quadrilateral ABCD ​ is inscribed in this circle.

Mathematics
2 answers:
Fofino [41]3 years ago
7 0
By the Inscribed Quadrilateral Theorem, a quadrilateral can only be inscribed if and only if opposite angles are supplementary.  This means that \angle D \text{ and } \angle B are supplementary, or add up to 180°.  This gives us the equation
(3<em>x</em> + 9)° + (2<em>x</em> - 4)° = 180°
Combine like terms:
5<em>x</em> + 5 = 180
Subtract 5 from each side:
5<em>x</em> + 5 - 5 = 180 - 5
5<em>x</em> = 175
Divide both sides by 5:
5<em>x</em>/5 = 175/5
<em>x</em> = 35
This means that m \angle D=3(35)+9=114&#10;\\m \angle B=2(35)-4 = 66&#10;\\m \angle A=2(35) + 3=73
We take these 3 angles away from 360 and we will have the measure of angle C:
360 - 114 - 66 - 73 = 107°<em />
enot [183]3 years ago
6 0

Answer:

62 is the answer for my k12 freinds

Step-by-step explanation:

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Step-by-step explanation:

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cestrela7 [59]

Answer:

See the attachment for what goes on your X diagram.

Rewrite: x² -7x +4x -28

Grouping: (x² -7x) +(4x -28) = x(x -7) +4(x -7) = (x +4)(x -7)

Step-by-step explanation:

The given quadratic is ...

... x² -3x -28 . . . . . a=1, b=-3, c=-28

a) The value at the top of the X diagram is the product a·c = 1·(-28) = -28.

The value at the bottom of the X diagram is the coefficient b = -3.

The values on the sides of the diagram are the factors of -28 that add up to make -3. These are -7 and 4. That is, ...

(-7)·(4) = -28

(-7)+(4) = -3

b) Since the two values on the sides of the diagram add up to give "b", the value of "b" in the equation can be rewritten as the sum of these two numbers. Doing that, we have ...

... x² -3x -28

... = x² +(-7+4)x -28

... = x² -7x +4x -28 . . . . . . order does not matter. It could also be x² +4x -7x -28

c) We can group pairs of terms in the rewritten expression and factor each pair.

... = (x² -7x) +(4x -28) . . . . . first pair has a common factor of x; second pair, 4

... = x(x -7) +4(x -7) . . . . . . . these terms now have a common factor: (x -7)

... = (x +4)(x -7) . . . . . . . . . . the complete factorization of x² -3x -28

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3 years ago
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