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telo118 [61]
2 years ago
12

A boy owns 7 pairs of pants, 3 shirts, 2 ties, and 6 jackets. How many different outfits can he wear to school if he must wear o

ne of each item?
He can wear different outfits.
Mathematics
2 answers:
SCORPION-xisa [38]2 years ago
8 0

Answer:

252 7 x 3 x 2

Step-by-step explanation:

lutik1710 [3]2 years ago
3 0

Answer:

252.

Step-by-step explanation:

We use the Multiplication Rule:

Number of outfits = 7 * 3 * 2 * 6 =  252.

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If you haven't seen it before, it works because when (x,y)=(a,b) we get (c-a)(b-b)=(d-b)(a-a), both sides zero, and when (x,y)=(c,d) we get (c-a)(d-b)=(d-b)(c-a), clearly equal sides.

Here we have

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Check:

We check each point is on the line

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(0, -9)

9(0) + 5(-9) = -45, good again


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