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prohojiy [21]
3 years ago
10

I need to solve for p and have a rationalized denominator

Mathematics
1 answer:
Travka [436]3 years ago
7 0

Answer:

p = \pm \dfrac{\sqrt{r(st - 1)}}{st - 1}

or

p = \dfrac{\sqrt{r(st - 1)}}{st - 1}

Step-by-step explanation:

t = \dfrac{p^2 + r}{p^2s}

p^2st = p^2 + r

p^2st - p^2 = r

p^2(st - 1) = r

p^2 = \dfrac{r}{st - 1}

p = \pm \sqrt{\dfrac{r}{st - 1}}

Your picture cuts out the assumption. If the assumption is that all variables are non-negative, then the answer is

p = \sqrt{\dfrac{r}{st - 1}}

p = \dfrac{\sqrt{r}}{\sqrt{st - 1}}}

p = \dfrac{\sqrt{r}}{\sqrt{st - 1}}} \times \dfrac{\sqrt{st - 1}}{\sqrt{st - 1}}

p = \dfrac{\sqrt{r} \sqrt{st - 1}}{\sqrt{st - 1}\sqrt{st - 1}}

p = \dfrac{\sqrt{r(st - 1)}}{st - 1}

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The simplified expressions are 2^-2 and 60^6

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