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prohojiy [21]
3 years ago
10

I need to solve for p and have a rationalized denominator

Mathematics
1 answer:
Travka [436]3 years ago
7 0

Answer:

p = \pm \dfrac{\sqrt{r(st - 1)}}{st - 1}

or

p = \dfrac{\sqrt{r(st - 1)}}{st - 1}

Step-by-step explanation:

t = \dfrac{p^2 + r}{p^2s}

p^2st = p^2 + r

p^2st - p^2 = r

p^2(st - 1) = r

p^2 = \dfrac{r}{st - 1}

p = \pm \sqrt{\dfrac{r}{st - 1}}

Your picture cuts out the assumption. If the assumption is that all variables are non-negative, then the answer is

p = \sqrt{\dfrac{r}{st - 1}}

p = \dfrac{\sqrt{r}}{\sqrt{st - 1}}}

p = \dfrac{\sqrt{r}}{\sqrt{st - 1}}} \times \dfrac{\sqrt{st - 1}}{\sqrt{st - 1}}

p = \dfrac{\sqrt{r} \sqrt{st - 1}}{\sqrt{st - 1}\sqrt{st - 1}}

p = \dfrac{\sqrt{r(st - 1)}}{st - 1}

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work out the circumference of this circle take pie to be 3.142and give your number to 1 decimal place and the radius is 11.2cm
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2 * 3.142 * 11.2 = 70.3808, to 1 decimal place is 70.4cm^2
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Prove the trigonometric identity
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Step-by-step explanation:

Man this one is a world of its own :D Just a quick question are you a fellow Add Math student in O levels i remember this question from back in the day :D Anyhow Lets get started

For this question we need to know the following identities:

1+tan^{2}x=sec^2x\\\\1+cot^2x=cosec^2x\\\\sin^2x+cos^2x=1

Lets solve the bottom most part first:

1-\frac{1}{1-sec^2x} \\\\

Take LCM

1-\frac{1}{1-sec^2x} \\\\\frac{1-sec^2x-1}{1-sec^2x} \\\\\frac{-sec^2x}{1-sec^2x} \\\\\frac{-(1+tan^2x)}{-tan^2x}

now break the LCM

\frac{-1}{-tan^2x}+\frac{-tan^2x}{-tan^2x}\\\\\frac{1}{tan^2x}+1\\\\cot^2x+1

because 1/tan = cot x

and furthermore,

cot^2x+1\\cosec^2x

now we solve the above part and replace the bottom most part that we solved with cosec^2x

\frac{1}{1-\frac{1}{cosec^2x} } \\\\\frac{1}{1-sin^2x} \\\\\frac{1}{cos^2x}\\\\sec^2x

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4 0
3 years ago
Sean read 15 of a book in 112 hours.
makvit [3.9K]
Sean read 15 of a book in = 112 hours, 
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Now, 12 of a book would be: 112/15 * 12 = 112/5 * 4 = 89.6

89.6 = 89 6/10 = 89 3/5

In short, Your Answer would be 89 3/5 hours

Hope this helps!
8 0
4 years ago
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