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sergejj [24]
3 years ago
11

If AB=5 and BC =10 is it possible that AC=4

Mathematics
1 answer:
son4ous [18]3 years ago
8 0
Yes depending on if ur talking about a triangle of not
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Evaluate 2/3 (10-6) 1/2 <br> ​
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Answer:

=  \frac{2}{3} (10 - 6) \frac{1}{2}

=  \frac{2}{3} (4) \frac{1}{2}

=  \frac{8}{3}  \times  \frac{1}{2}

=  \frac{4}{3}

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2 years ago
Which of the following are valid names for the given polygon?
DIA [1.3K]
<span>When naming a polygon, the letters must be connected. It shouldn't jump from one letter to the other on different sides. 
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E doesn't work because K isn't directly connected to N.</span>

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2 years ago
Carmen found m∠1 this way:<br><br> Is her answer correct? Explain why or why not.
34kurt

Answer:

She is not correct because ∠1 is an alternate exterior angle with ∠3, not the angle that measures 105°. So m∠1 = 75°.

Step-by-step explanation:

3 0
2 years ago
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What theorem can be used to prove these
VladimirAG [237]

Answer:

hl is right answer may be

5 0
2 years ago
If triangle ABC with vertices A(-2, -5), B(-3, 2), and C (1, -2) a right triangle?
V125BC [204]
Hello :
<span>A(-2, -5), B(-3, 2), and C (1, -2) 
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</span> AB² = ( -3  +2   )² +  ( 2  +5  )² =50
AC² = ( 1  +2  )² +  ( -2  +5   )²  =18
BC² = (  1 +3  )² +  ( -2  - 2  )²  = 32
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7 0
3 years ago
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