You first subtract the speed at which the man is moving (11 m/s) from the rate the boat is moving (12.4 m/s). Which equals 1.4, then divide it by 6 meters, as the man is moving relative to the boat.
It therefore equals 4.29 s
The isolation period was the time that Issac Newton used to develop his genius. In 1665, when his university was closed because of bubonic plague, Issac Newton went to a relative's farm in Lincolnshire and spent the next two years there in solitary academic pursuits. It was during this time that he made major advances in formation of calculus, he also worked on the revolutionary theory of the nature of light and colour. It was during this period as well that he gained insights into planetary movement and he also develop the early versions of his laws of motion.
(a) The acceleration of the two block is determined as 0.93 m/s².
(b) The tension in the string is 5.78 N.
<h3>Net force on the aluminum block</h3>
The net force on the aluminum block is calculated as follows;
<h3>Net force on the copper block</h3>
The net force on the copper block is calculated as follows;
where;
- T is tension in the string
- ma is mass of aluminum
- mc is mass of copper
- g is acceleration due to gravity
Solve for T using (1) and (2)
<h3>Tension in the string</h3>
From equation (1);
T = μm_ag + m_aa
T = 0.2(2)(9.8) + 2(0.93)
T = 5.78 N
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Answer:
a. one-fourth its original value.
Explanation:
Sound is threated as a spherical wave. The intensity of the sound is inversely proportional to the area of the wavefront (). Therefore, it is inversely proportional to the square of the distance (r) to the sound source. So, if you double your distance, the intensity of the sound reduces to one-fourth its original value.
Answer:
The cart moved away from the starting point between 8 s and 10 s.
Explanation:
Given that :
Which of these does NOT describe the cart’s motion on this graph?
The cart was at rest between 5 s and 7 s : From the distance of golf cart Vs time graph ; the car was at rest between 5s and 7s as the graph was flat with that time interval, meaning there was no change in distance.
The cart moved toward the starting point between 7 s and 12 s. : The graph depicts a negative slope at this time interval as the distance from starting point fell from about 26 m to 10 m
The cart moved away from the starting point between 8 s and 10 s. : At this time interval, the cart moved towards the starting not and not away. This could be seen in the decrease in Distance from starting point between the tune interval.
The cart moved away from the starting point between 2 s and 5 s. - - > The cart moved away from the starting point, with the positive slope signifying an increase in distance.
Therefore, The cart moved away from the starting point between 8 s and 10 s does not describe the motion of the cart on the graph.