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Stella [2.4K]
4 years ago
6

1. Study the map. What do you think divergent boundary means ? What about convergent boundary ?

Physics
1 answer:
olasank [31]4 years ago
5 0

Answer:

Convergence generally means coming together, while divergence generally means moving apart. In the world of finance and trading, convergence and divergence are terms used to describe the directional relationship of two trends, prices, or indicators.

Hope this helps! :)

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Large bodies of water provide moisture to winds blowing across them creating what is called effects
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7 0
3 years ago
Why does the quantity of helium found in the universe support the big bang theory?
Nostrana [21]
The correct option is D.
The big bang theory is the scientific theory that explains how the universe came to exist. The theory explains how the universe expanded due to high temperature and density. Scientists believed that the first nuclei were formed few minutes after the bing bang occurred via a process called bing bang nucloesynthesis. During this process helium and hydrogen were formed and the amount of helium found correspond to the amount predicted by scientists.
6 0
4 years ago
You have 10 ohm and a 100 ohm resistor in parallel. You place this equivalent resistance in series with an LED, which is rated t
Nataly [62]

Answer:

Approximately \rm 2.0\; V.

Approximately \rm 30 \; mA. (assumption: the LED here is an Ohmic resistor.)

Explanation:

The two resistors here R_1= 10\; \Omega and R_2= 100\; \Omega are connected in parallel. Their effective resistance would be equal to

\displaystyle \frac{1}{\dfrac{1}{R_1} + \dfrac{1}{R_2}} = \frac{1}{\dfrac{1}{10} + \dfrac{1}{100}} = \frac{10}{11} \; \Omega.

The current in a serial circuit is supposed to be the same everywhere. In this case, the current through the LED should be 20\; \rm mA = 0.020\; \rm A. That should also be the current through the effective \displaystyle \rm \frac{10}{11} \; \Omega resistor. Make sure all values are in standard units. The voltage drop across that resistor would be

V = I \cdot R = 0.020 \times \dfrac{10}{11} \approx 0.182\; \rm V.

The voltage drop across the entire circuit would equal to

  • the voltage drop across the resistors, plus
  • the voltage drop across the LED.

In this case, that value would be equal to 1.83 + 0.182 \approx 2.0\; \rm V. That's the voltage that needs to be supplied to the circuit to achieve a current of 20\; \rm mA through the LED.

Assuming that the LED is an Ohmic resistor. In other words, assume that its resistance is the same for all currents. Calculate its resistance:

\displaystyle R(\text{LED}) = \frac{V(\text{LED})}{I(\text{LED})}= \frac{1.83}{0.020} \approx 91.5\; \Omega.

The resistance of a serial circuit is equal to the resistance of its parts. In this case,

\displaystyle R = R(\text{LED}) + R(\text{Resistors}) = 91.5 + \frac{10}{11} \approx 100\; \Omega.

Again, the current in a serial circuit is the same in all appliances.

\displaystyle I = \frac{V}{R} = \frac{3}{100} \approx 0.030\; \rm A = 30\; mA.

7 0
3 years ago
How many covalent bonds can be formed by Nitrogen? Please explain
natka813 [3]
Three bonds

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6 0
3 years ago
The block in the diagram below is AT REST. However, the tension in the cable is not the only thing holding the block back. Stati
Vedmedyk [2.9K]

Answer:

The  tension in the rope is 229.37 N.

Explanation:

Given:

Mass of the block is, m=33.2\ kg

Coefficient of static friction is, \mu = 0.214

Angle of inclination is, \theta = 31.5°

Draw a free body diagram of the block.

From the free body diagram, consider the forces in the vertical direction perpendicular to inclined plane.

Forces acting are mg\cos \theta and normal N. Now, there is no motion in the direction perpendicular to the inclined plane. So,

N=mg\cos \theta\\N=(33.2)(9.8)\cos (31.5)\\N=277.415\ N

Consider the direction along the inclined plane.

The forces acting along the plane are mg\sin \theta and frictional force, f, down the plane and tension, T, up the plane.

Now, as the block is at rest, so net force along the plane is also zero.

T=mg\sin \theta+f\\T=mg\sin \theta +\mu N\\T= (33.2)(9.8)(\sin (31.5)+(0.214\times 277.415)\\T= 170+59.37\\T=229.37\ N

Therefore, the  tension in the rope is 229.37 N.

3 0
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