Answer:

Using the frequency distribution, I found the mean height to be 70.2903 with a standard deviation of 3.5795
Step-by-step explanation:
Given
See attachment for class
Solving (a): Fill the midpoint of each class.
Midpoint (M) is calculated as:

Where
Lower class interval
Upper class interval
So, we have:
Class 63-65:

Class 66 - 68:

When the computation is completed, the frequency distribution will be:

Solving (b): Mean and standard deviation using 1-VarStats
Using 1-VarStats, the solution is:


<em>See attachment for result of 1-VarStats</em>
4x(3+2)-6x1= 14 is the answer
Answer:
1 pi: 3pi
Step-by-step explanation:
Step 1: Formula of surface area and volume of sphere
Surface area of sphere = 4 x pi x r^2
Volume of sphere = <u>4</u> x pi x r^3
3
Step 2: Apply values in the formula
r = radius
radius = diameter/2
r=18/2 = 9
S.A = 4 x pi x 9^2
S.A = 324pi
Volume = <u>4</u> x pi x 9^3
3
Volume = 972pi
Step 3 : Show in ratio
Surface area : Volume
324pi : 972pi
= 1 pi: 3pi
You add half of the coefficient of x and square it.
What you do on one side,you must do it on the other.
In the rhombus, the diagonals are perpendicular.
We know, the sum of the measures of the triangle is equal 180°.
Therefore we have the equation:

<em>combine like terms</em>

<em>subtract 75 from both sides</em>
<em>divide both sides by 5</em>

<h3>Answer: x = 21°</h3>