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3 years ago

Can someone help me on this math problem.

Mathematics

1 answer:

nekit [7.7K]3 years ago

4 0

In the rhombus, the diagonals are perpendicular.

We know, the sum of the measures of the triangle is equal 180°.

Therefore we have the equation:

$(2x-15)+3x+90=180$

$2x-15+3x+90=180$ <em>combine like terms</em>

$(2x+3x)+(-15+90)=180$

$5x+75=180$ <em>subtract 75 from both sides</em>

$5x=105$ <em>divide both sides by 5</em>

$\boxed{x=21}$

<h3>Answer: x = 21°</h3>

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Please help and thank you.

Marina CMI [18]

Answer:

400 ft elevation at 1 km and 3 km from the start
300 ft/km average rate of change over the first 4 km

length = 3.5 cm
width = 3.5 cm
height = 7.0 cm

6 mo: $1018.14
5 yrs: $1196.89
avg incr: $3.28 per month

Step-by-step explanation:

A graphing calculator is handy for solving problems involving cubic polynomials. You're interested in where the elevation is 400 ft. Since the value of f(x) is in hundreds of feet, you want to find x such that f(x) = 4.

Values of x where that is the case are x=1 and x=3, representing distances of 1 km and 3 km from the start of the road.

The average rate of change of elevation is the difference in elevation divided by the difference in distance from the start:

average rate of change = (f(4) -f(0) hundred ft)/((4 - 0) km)

= (19 -7)/4 hundred feet/km

= 12/4 hundred feet/km = 300 ft/km

___

You want to find x when ...

A(x) = 122.5 cm²

10x² = 122.5 cm² . . . . substitute the given expression for A(x)

x² = 12.25 cm² . . . . . . divide by 10

x = √(12.25 cm²) = 3.5 cm . . . . take the square root

The diagram tells you ...

length = width = x = 3.5 cm

height = 2x = 7.0 cm

___

Evaluate the given expression for the different values of m:

$1000·1.003^6 ≈ $1018.14 . . . . 6-month value

$1000·1.003^60 ≈ $1196.89 . . . . 5-year value

The increase is $1196.89 -1000.00 = $196.89. That increase took place over 60 months, so the average increase per month is ...

$196.89/(60 mo) ≈ $3.28 per mo . . . . average per month over 5 years

8 0

4 years ago

PLEASE PLEASE HELP

nekit [7.7K]

Answer:68.3 degrees

Step-by-step explanation:

The diagram of the triangle ABC is shown in the attached photo. We would determine the length of side AB. It is equal to a. We would apply the cosine rule which is expressed as follows

c^2 = a^2 + b^2 - 2abCos C

Looking at the triangle,

b = 75 miles

a = 80 miles.

Angle ACB = 180 - 42 = 138 degrees. Therefore

c^2 = 80^2 + 75^2 - 2 × 80 × 75Cos 138

c^2 = 6400 + 5625 - 12000Cos 138

c^2 = 6400 + 5625 - 12000 × -0.7431

c^2 = 12025 + 8917.2

c = √20942.2 = 144.7

To determine A, we will apply sine rule

a/SinA = b/SinB = c/SinC. Therefore,

80/SinA = 144.7/Sin 138

80Sin 138 = 144.7 SinA

SinA = 53.528/144.7 = 0.3699

A = 21.7 degrees

Therefore, theta = 90 - 21.7

= 68.3 degees

8 0

3 years ago

Two trains arrived at a station at 2:55 P.M., with one arriving on Track A, and the other arriving on Track B. Trains arrive on

My name is Ann [436]

Answer:

B) 5:19 P.M.

Step-by-step explanation:

Given that two trains arrived at a station at 2:55 P.M., with one arriving on Track A, and the other arriving on Track B. Trains arrive on Track A every 16 minutes, and they arrive on Track B every 18 minutes.

Now we need to find about at what time will trains next arrive at the same time on both tracks.

Then next time trains arrive at the same time on both tracks. can be found by taking least common multiple of 16 and 18 minutes.

Multiples of 16 and 18 are

16 32 48 64 80 96 112 128 144 160

18 36 54 72 90 108 126 144 162 180

Least common multiple of both is 144

Hence both trains will arrive at the same time after 144 minutes

or at (2:55 PM+144 minutes)

= (2 hours 55 min)+(144 min) PM

= (2 hours 55 min)+(2 hours 24 min) PM

= 5 hours 19 minutes

Hence correct choice is B) 5:19 P.M.

7 0

3 years ago

2. Which equation is true if x= -5?<br> A. 7 - x = 2<br> B. 3x = -15<br> C. -2 + x = -3

vaieri [72.5K]

Answer:

Step-by-step explanation:

3*5 is 15 and since its a negative 5 your answer will be negative

5 0

3 years ago

Find the length and width of a rectangle that has a perimeter of 100 meters and a maximum area

madreJ [45]

A rectangle with maximum area is always a square

a square has the same length and width.

to find the length of the side of a square with the known area, you would take the square root of the area

so in this case, the side length = square root of 100

square root (100) = 10 ( check: 10 x 10 = 100)

so both the length and the width equal 10 meters

8 0

3 years ago