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Artyom0805 [142]
3 years ago
13

A company makes electronic gadgets. One out of every 50 gadgets is faulty, but the company doesn't know which ones are faulty un

til a buyer complains. Suppose the company makes a $3 profit on the sale of any working gadget, but suffers a loss of $80 for every gadget because they have to repair the unit. Check weather the company can expect a profit in the long term.
Mathematics
1 answer:
Talja [164]3 years ago
6 0

Answer:

Yes, the company can expect a profit in the long term

Step-by-step explanation:

In this question, we are to project if a company is expected to make a profit or loss given the information in the question.

Let’s use the scenario of 50 gadgets produced.

1 is expected to be faulty, while 49 is thus expected to work perfectly.

Now, on this 49 sold, there is an expectancy of $3 profit. Hence, this means that for a batch of 50 gadgets produced, the amount of expected profit will be 49 * 3 = $147

The amount that would be used to repair the faulty unit is $80. If we subtract this from the total expected profit, we have $147-$80 = $67

Hence, per 50 gadgets sold, a total of $67 in profit is to be expected

This means profit is expected in the long tey

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Let ℤ17 be the ring of integers modulo 17, and let ℤ×17 be the group of units of ℤ17 under multiplication. Which of the followin
joja [24]

Answer:  The correct option is (E) I, II and III.

Step-by-step explanation:  Given that ℤ17 be the ring of integers modulo 17, and let ℤ×17 be the group of units of ℤ17 under multiplication.

We are to select the correct generators of ℤ×17.

According to the given information, we can write

ℤ17 = {0, 1, 2, 3, . . . , 16}

and

ℤ×17 = {1, 2 , 3 , . . . 16}.

The generators of ℤ×17 are those elements which are co prime to 17.

Since all the elements from 1 to 16 are co prime to 17, so all the elements of the set  ℤ×17 are its generators.

Therefore, 5, 8 and 16, all are generators. So, i, ii and iii are generators.

Thus, (E) is the correct option.

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3 years ago
!!!!Pls help me hurry !!!! I don’t know what I’m doing
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For the 3 you multiply the equations of f(x) and g(x) by each other and you do that by foiling then you combine like terms. After that the terms A, B,C D, and E are in the answer which is...
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The functions graphed show the snowfall, in inches, in two cities after x hours.
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The answer Fam is............. <span>Smithville had a faster rate of snowfall., And..</span><span>Snow fell in Smithville at a rate of 4 inches per hour.</span>
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Y varies directly with x, and y = 120 ib when x = 50 ib. Find y if x = 40 ib
Llana [10]
Y = kx is the direct variation equation.
Use the x and y given to find k. After finding k use it to write a new equation.
120=k*50
Divide by 50 on both sides
120/50=k 12/5=k
y = (12/5)(40) y=96
8 0
3 years ago
A teacher wants to see if a new unit on factoring is helping students learn. She has five randomly selected students take a pre-
sattari [20]

Answer:

Step-by-step explanation:

Given the sample data

Pre-test... 12 14 11 12 13

Post-Test 15 17 11 13 12

The mean of pre-test

x = ΣX / n

x = (12+14+11+12+13) / 5

x = 12.4

The standard deviation of pre-test

S.D = √Σ(X-x)² / n

S.D = √[(12-12.4)²+(14-12.4)²+(11-12.4)²+(12-12.4)²+(13-12.4)² / 5]

S.D = √(5.2 / 5)

S.D = 1.02.

The mean of post-test

x' = ΣX / n

x' = (15+17+11+13+12) / 5

x' = 13.6

The standard deviation of post-test

S.D' = √Σ(X-x)² / n

S.D' = √[(15-13.6)²+(17-13.6)²+(11-13.6)²+(13-13.6)²+(12-13.6)² / 5]

S.D = √(23.2 / 5)

S.D = 2.15

Test value

t = (sample difference − hypothesized difference) / standard error of the difference

t = [(x-x') - (μ- μ')] / (S.D / n — S.D'/n)

t = (12.4-13.6) - (μ-μ')/ (1.02/5 - 2.15/5)

-1.5 = -1.2 - (μ-μ') / -0.226

-1.5 × -0.226 = -1.2 -(μ-μ')

​0.339 = -1.2 - (μ-μ')

(μ-μ') = -1.2 -0.339

μ-μ' = -1.539

Then, μ ≠ μ'

We can calculate our P-value using table.

This is a two-sided test, so the P-value is the combined area in both scores.

The p-value is 0.172

The p value > 0.1

6 0
3 years ago
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