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sergey [27]
3 years ago
15

i a man even number beetween 50 and 99 i am a multiple of 9 my tens digit is 5 more than my units digit

Mathematics
1 answer:
vodomira [7]3 years ago
6 0
Hello,
multiple of 9 betheen 50 and 99 are :54,63,72,81,99
and 54,72  are even.
5-4=1 and not 5
7-2=5 ok

72 is the number searched.
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Solve by substitution. Please show work<br> -x+9y=-5<br> x-5y=1
kkurt [141]

Let's solve for x.

−x+9y=−5

Step 1: Add -9y to both sides.

−x+9y+−9y=−5+−9y

−x=−9y−5

Step 2: Divide both sides by -1.

−x ÷ −1 = −9y−5 ÷ −1

x=9y+5

THE ANSWER FOR THE OTHER EQUATION: (x-5y=1)

Let's solve for x.

x−5y=1

Step 1: Add 5y to both sides.

x−5y+5y=1+5y

x=5y+1

Answer:

x=5y+1

I hope this helped I was a little confused on what your problem meant...so if this is not what you asked for just lmk so I can fix it for you :)

3 0
2 years ago
to increase the mean of 4 numbers by 2, by how much would the sum of the 4 numbers have to increase? check image.
solong [7]

Answer:

8

Step-by-step explanation:  

x=average

(x+x+x+x)/4=average

to increase x by 2 you add 2

x+2=average

(x+2+x+2+x+2+x+2)=4=(4x+8)/4=x+2

you'd have to increase the sum by 8 to make the numbers' averages' go up by 2

8 0
2 years ago
Can someone PLEASE help me with Trigonometry???
Svetach [21]
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but anyway, the numerator will give the angles, and θ is just half of each

\bf \theta=\cfrac{sin^{-1}\left( \frac{7\pm\sqrt{53}}{2} \right)}{2}\\\\&#10;-------------------------------\\\\&#10;sin^{-1}\left( \frac{7+\sqrt{53}}{2} \right)\implies sin^{-1}(7.14)\impliedby \textit{greater than 1, no good}&#10;\\\\\\&#10;sin^{-1}\left( \frac{7-\sqrt{53}}{2} \right)\implies sin^{-1}(-0.14) \approx -8.05^o&#10;\\\\\\&#10;\theta=\cfrac{-8.05}{2}\implies \theta=-4.025

ok... that's a negative tiny angle, is in the 4th quadrant, if we stick to the range given, from 0 to 360, so we have to use the positive version of it, 360-4.025

so the angle is 355.975°

now, the 3rd quadrant has another angle whose sine is negative, so... if we move from the 180° line down by 4.025, we end up at 184.025°

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7 0
3 years ago
Suppose an angle measuring "1 Gip" subtends an arc that is 1/15th of the circumference of any circle centered at its vertex, and
Kruka [31]

Answer:

(a) (i) 8/15

    (ii) 4.8 Quips

(b) 5.82 Quips

Step-by-step explanation:

(a)

(i) 1 Gip = 1/15 of a circumference

8 Gips = 8 × 1/15 of a circumference = 8/15 of circumference

(ii) 1 Gips = 1/15 of a circumference

15 Gips = 1 circumference

1 Quips = 1/9 of a circumference

9 Quips = 1 circumference

∴ 15 Gips = 9 Quips

1 Gip = 9/15 Quips

8 Gips = 8 × 9/15 Quips = 4.8 Quips

(b) 9.7 Gips = 9.7 × 9/15 Quips = 5.82 Quips

8 0
3 years ago
-2 ( 6 + 7n ) = 3n + 5
jek_recluse [69]

Answer:

n = -1

Explanation:

First we need to distribute the -2 throughout the variable getting us to

-12 - 14n = 3n + 5

Then we need to move the variable n to one side and isolate it. To do this, subtract 3n from both sides and add 12 to both sides.

-17n = 17

Now, we need to remove the co-efficient from n, so we need to divide both side by -17.

n = -1

7 0
3 years ago
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