Given :
A particle moves in the xy plane starting from time = 0 second and position (1m, 2m) with a velocity of v=2i-4tj .
To Find :
A. The vector position of the particle at any time t .
B. The acceleration of the particle at any time t .
Solution :
A )
Position of vector v is given by :
B )
Acceleration a is given by :
Hence , this is the required solution .
Answer:2n+13=75 n=31
Answer:
3500 280
Step-by-step explanation:
280/3500
280 divided by 3500 times 100 (type this into a calculator)
its 8 her savings are 8 percent of her income
1.) Gallon
2.) Pound
3.) Foot
Hope this helps :)
steve becaise its less secinds