The answer to this question is B.
Pathogens can adapt more quickly than hosts since they have higher populations and faster generation periods.
Pathogens, of course, have the advantage in this evolutionary game because they can change far more quickly than the hosts—especially in long-lived animals like humans—due to their high population numbers and rapid generation rates. The relationship between surface area and complement activation shows how bacterial pathogenicity may be influenced by tiny size. The region of the microbial surface may also have a role in their action since other antimicrobial agents are focused there. A pathogen reacts with the host and creates infection, which results in the host being ill. Any dangerous microbial agent, including bacteria, viruses, protozoa, fungi, and helminths, might be considered a pathogen.
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The villi of the small intestine use active transport to take up nutrients after concentration has reached equilibrium.
<h3>What is Active transport?</h3>
Active transport may be defined as the process that occurs against the concentration gradient and is mediated by carrier proteins. Metabolic energy is used to move ions or molecules against a concentration gradient.
During the process of digestion, the villi in the small intestine enthrall the soluble nutrients gradually. Over time, the concentration of nutrients in the villi acquires an equilibrium with the concentration in the gut. Until here, the nutrient uptake is carried by the process of passive diffusion.
But after attaining the equilibrium, the nutrient uptake is carried by the process of active transport.
The complete question is as follows:
What part of the body uses active transport to take up nutrients after concentration has reached equilibrium?
- Lungs
- Stomach
- Small intestine
- Liver
Therefore, the correct option for this question is C, i.e. small intestine.
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We know that Hardy-Weinberg conditions include the following equations:

where 
And where p = dominant, and q = recessive; this means that
is equal to the homozygous dominant,
is the heterozygous, and
is the homozygous recessive .
So we have 100 total cats, with 4 having the recessive white coat color. That means we have a ratio of
or 0.04. Let that equal our
value.
So when we solve for q, we get:


Now that we have our q value, we can use the other equation to find p:



So then we can solve for our heterozygous population:

This is the ratio of the population. So we then multiply this number by 100 to get the number of cats that are heterozygous:

So now we know that there are 32 heterozygous cats in the population.
Answer:
you are correct and exponential growth is also imppossible
Explanation: