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klasskru [66]
3 years ago
15

Orange 20 40 60

Mathematics
2 answers:
ElenaW [278]3 years ago
7 0
Number of medium cherry slices : 10
number of medium orange slices : 40

ratio of cherry to orange : 10/40 reduces to 1/4 or 1:4 or 1 to 4
Leno4ka [110]3 years ago
6 0
Cherry d four to one
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I need help with question number 2 please !!
Tatiana [17]

Answer:

Step-by-step explanation:

15.5884573 i

5 0
3 years ago
Bill weights 120 pounds and is gaining 10 pounds each month. Phil weights 150 pounds and is gaining 4 pounds each month. How man
Leviafan [203]

The answer should be 3 months

4 0
2 years ago
Read 2 more answers
Please show me step by step on how to solve this.
Readme [11.4K]
Well, you have to be given an interval. That is not an interval.

You should be given something like 1 \leq x \leq 2

If you add those fractions up you'll just get a point on the number line.

Find the LCD for all of them which is 9/6 - 4/6 + 3/6 = 8/6 = 2/3

You'll end up with a point on 2/3 
7 0
3 years ago
What is the equation of the graphed line in point-slope form?
SSSSS [86.1K]
First, we find the slope
(4,0)(0,-3)
slope = (-3 - 0) / (0 - 4) = -3/-4 = 3/4

there can be 3 possible answers for this..
y - y1 = m(x - x1)
slope(m) = 3/4
using points (4,0)...x1 = 4 and y1 = 0
now we sub
y - 0 = 3/4(x - 4) <== this is one answer

y - y1 = m(x - x1)
slope(m) = 3/4
using points (0,-3)...x1 = 0 and y1 = -3
now we sub
y - (-3) = 3/4(x - 0) =
y + 3 = 3/4(x - 0) <== here is another answer

y - y1 = m(x - x1)
slope(m) = 3/4
using points (-4,-6)...x1 = -4 and y1 = -6
now we sub
y - (-6) = 3/4(x - (-4) =
y + 6 = 3/4(x + 4) <=== and here is another answer

5 0
3 years ago
Find a vector parametric equation r⃗(t) for the line through the points P=(1,0,−2) and Q=(1,5,1) for each of the given condition
const2013 [10]
So the question ask to find and calculate the vector parametric equation r(t) for the line through the points P=(1,0,-2) and Q(1,5,1) for each given condition. And the possible vector parametric equation is <1,2,-2>+t/4<1,5,3>. I hope you are satisfied with my answer and feel free to ask for more 
7 0
3 years ago
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