Answer:
The real roots are
and 
The sum of the squares of these roots is 
Step-by-step explanation:
The given quadratic equation is 
has two real roots.
To find the roots .
Dividing the above equation by 2
For quadratic equation 
the solution is 
Where a and b are coefficents of 
and x respectively, c is a constant.
For given quadratic equation
a=4, b=6, c=-7
The real roots are
and
Now to find the sum of the squares of these roots
![\left[\frac{-3+\sqrt{37}}{4}+\frac{(-3-\sqrt{37})}{4}\right]^2=\frac{-3+\sqrt{37}-3-\sqrt{37}}{4}](https://tex.z-dn.net/?f=%5Cleft%5B%5Cfrac%7B-3%2B%5Csqrt%7B37%7D%7D%7B4%7D%2B%5Cfrac%7B%28-3-%5Csqrt%7B37%7D%29%7D%7B4%7D%5Cright%5D%5E2%3D%5Cfrac%7B-3%2B%5Csqrt%7B37%7D-3-%5Csqrt%7B37%7D%7D%7B4%7D)
![\left[\frac{-3+\sqrt{37}}{4}+\frac{(-3-\sqrt{37})}{4}\right]^2=\frac{-3}{2}](https://tex.z-dn.net/?f=%5Cleft%5B%5Cfrac%7B-3%2B%5Csqrt%7B37%7D%7D%7B4%7D%2B%5Cfrac%7B%28-3-%5Csqrt%7B37%7D%29%7D%7B4%7D%5Cright%5D%5E2%3D%5Cfrac%7B-3%7D%7B2%7D)
Therefore the sum of the squares of these roots is
Answer:
{(-6,-6), (-2,-2), (7,-6), (-5,0)}
Step-by-step explanation:
Function: Every domain (x-value) has only one range (y-value)
The other choices had an x-value that had more than one y-value, which makes only this one a function.
Hope this helped :)
Start with the smallest square number, it is zero but assuming they don’t want this answer so we will try with 1:
So n * 10 = 1
n= 1/10
n= 0.1
Answer:
Angle A = 180
Step-by-step explanation:
180=7x+40
Subtract 40 from both sides
140 = 7x
Divide 7 from both sides
20=x
Substitue 20 in for x
7(20)+40
140+40 = 180
