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2 years ago

CAN ANYONE DO IT, IT IS EASY

Mathematics

2 answers:

Ray Of Light [21]2 years ago

6 0

Answer: 31

Step-by-step explanation:

180-20-35 = 125 (bottom triangle)

180 - 156 = 24

125 + 24 = 149

180-149 = your answer

amid [387]2 years ago

3 0

A the degree of ? is 2

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2^24 x 3^2 x 1 hhhhhhhhhhhhhhhhhh

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3 years ago

How many integers are there between -8 and 2?<br><br> Group of answer choices

Dahasolnce [82]

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9 numbers between -8 and 2.

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3 years ago

Find the moment of inertia about the y-axis of the thin semicirular region of constant density

arlik [135]

The moment of inertia about the y-axis of the thin semicircular region of constant density is given below.

$\rm I_y = \dfrac{1}{8} \times \pi r^4$

<h3>What is rotational inertia?</h3>

Any item that can be turned has rotational inertia as a quality. It's a scalar value that indicates how complex it is to adjust an object's rotational velocity around a certain axis.

Then the moment of inertia about the y-axis of the thin semicircular region of constant density will be

$\rm I_x = \int y^2 dA\\\\I_y = \int x^2 dA$

x = r cos θ

y = r sin θ

dA = r dr dθ

Then the moment of inertia about the x-axis will be

$\rm I_x = \int _0^r \int _0^{\pi} (r\sin \theta )^2 \ r \ dr \ d\theta\\\\\rm I_x = \int _0^r \int _0^{\pi} r^3 \sin ^2\theta \ dr \ d\theta$

On integration, we have

$\rm I_x = \dfrac{1}{8} \times \pi r^4$

Then the moment of inertia about the y-axis will be

$\rm I_y = \int _0^r \int _0^{\pi} (r\cos\theta )^2 \ r \ dr \ d\theta\\\\\rm I_y = \int _0^r \int _0^{\pi} r^3 \cos ^2\theta \ dr \ d\theta$

On integration, we have

$\rm I_y = \dfrac{1}{8} \times \pi r^4$

Then the moment of inertia about O will be

$\rm I_o = I_x + I_y\\\\I_o = \dfrac{1}{8} \times \pi r^4 + \dfrac{1}{8} \times \pi r^4\\\\I_o = \dfrac{1}{4} \times \pi r^4$

More about the rotational inertia link is given below.

brainly.com/question/22513079

#SPJ4

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2 years ago

Find the midpoint of ab.<br> a) (3,1)<br> b) (1,1)<br> c) (10,4)<br> d) (4,4)

Mrrafil [7]

The answer is b) (1;1)

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3 years ago

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