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4vir4ik [10]
3 years ago
13

A print company will print business cards for $.10 each plus a setup charge of $12. Another print company offers business cards

for $.12 each with a setup charge of $10. What number of business cards will cost the same amount from either printer?
Mathematics
1 answer:
bonufazy [111]3 years ago
3 0

Let the number of cards equal x.

Set up an equation for both companies, set equal to each other and solve for x.

0.10x + 12 = 0.12x + 10

Subtractb0.10x from both sides:

12 = 0.02x + 10

Subtract 10 from both sides:

2 = 0.02x

Divide both sides by 0.02:

X = 2/0.02

X = 100

100 cards would be the same price for both companies.

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Amiraneli [1.4K]

Answer:

Option 1) p ←→ q

Step-by-step explanation:

The given statement is a combination of two phrases with a connective word.

Phrase 1 - The Fratellis will be arrested.

We consider this phrase as phrase p.

Phrase 2 - If the police believe chunk.

Phrase q.

Now these statements p and q are connected with a connecting word "If only and only".

When two phrases are connected by the connecting words "Only and only if", this connecting word is called as biconditional operator.

p (connecting word) q

p ( If and only if) q

p ←→ q

Therefore, Option 1) p ←→ q is the answer.

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3 years ago
When doing blood testing for a viral infection, the procedure can be made more efficient and less expensive by combining partial
Serjik [45]

Answer:

0.1694 = 16.94% probability of a positive result for three samples combined into one mixture.

Step-by-step explanation:

For each test, there are only two possible outcomes. Either it is positive, or it is negative. The probability of a test being positive or negative is independent of any other test, which means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

The probability of an individual blood sample testing positive for the virus is 0.06.

This means that p = 0.06

If samples from three people are combined and the mixture tests negative, we know that all three individual samples are negative. Find the probability of a positive result for three samples combined into one mixture.

It will be positive if at least one of the tests is positive, that is:

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In which

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{3,0}.(0.06)^{0}.(0.94)^{3} = 0.8306

Then

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0.1694 = 16.94% probability of a positive result for three samples combined into one mixture.

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