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agasfer [191]
3 years ago
15

How do you find the range of a linear graph

Mathematics
1 answer:
LUCKY_DIMON [66]3 years ago
8 0
The range is the possible y-values of the graph. If you have a specific equation, post it.
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A rectangle is formed by placing two identical squares side by side
julsineya [31]

Answer:

200

Step-by-step explanation:

If there are 2 squares next to eachother with the same area, then their perimeter is 6*sidelength.

60 = 6*sidelength

10 = sidelength

Square the sidelength to find the area of the square. 10^2 = 100

Multiply that by 2 to find the area of the rectangle. 100*2 =

200

4 0
3 years ago
Please help and explain how
azamat
18, 42, and 27. they were all times by 2
7 0
3 years ago
What is greater 1/5 , 1/4 , or 1/3
olya-2409 [2.1K]
1/3 is greater than 1/5 and 1/4.
5 0
2 years ago
Read 2 more answers
Select ALL the correct answers.
Marina CMI [18]

Answer:

The median of A is the same as the median of B.

The interquartile range of B is greater than the interquartile range of A.

Step-by-step explanation:

Given that:

A = number of runs allowed in first 9 games

A = {1, 4, 2, 2, 3, 1, 1, 2, 1}

Rearranging A : 1, 1, 1, 1, 2, 2, 2, 3, 4

Median A = 1/2(n + 1) th term

Median A = 1/2(10) = 5th term = 2

Q1 of A = 1/4(10) = 2.5th term = (1 + 1)/ 2 = 1

Q3 of A = 3/4(10) = 7.5th term = (2+3)/2 = 2.5

Interquartile range = Q3 - Q1 = 2.5 - 1 = 1.5

Number of runs allowed in 10th game = 9

B = {1, 4, 2, 2, 3, 1, 1, 2, 1, 9}

Rearranging B = 1, 1, 1, 1, 2, 2, 2, 3, 4, 9

Median A = 1/2(n + 1) th term

Median A = 1/2(11) = 5.5th term = (2+2)/2 = 2

Q1 of A = 1/4(11) = 2.75th tetm = (1 + 1)/ 2 = 1

Q3 of A = 3/4(11) = 8.25th term = (3+4)/2 = 3.5

Interquartile range = Q3 - Q1 = 3.5 - 1 = 2.5

Median A = 2 ; median B = 2

IQR B = 2.5 ; IQR A = 1.5 ; IQR B > IQR A

7 0
2 years ago
Andy is alone in the wilderness and eager to get back to camp. Looking at his map (shown below), Andy sees that he might be able
BabaBlast [244]

Answer:

9.5 km

Step-by-step explanation:

8 0
3 years ago
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