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3 years ago

I need help converting 25 oz to g

Mathematics

2 answers:

GenaCL600 [577]3 years ago

8 0

Answer: 708.738 because 1 oz = 28.35 grams

25 x 28.35 = 708.738

Step-by-step explanation:

s2008m [1.1K]3 years ago

3 0

The answer is 708.74 grams

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A woman has 19 coins in her pocket, all of which are dimes and quarters. If the total value of the coins is $ 3.55, how many dim

mars1129 [50]

13 quarters = 3.25 and 3 dimes =.30 which = 3.55

4 0

3 years ago

If -y-2x^3=Y^2 then find D^2y/dx^2 at the point (-1,-2) in simplest form

algol13

Answer:

$\frac{d^2y}{dx^2} = \frac{-4}{3}$

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Algebra I

Factoring

Calculus

Implicit Differentiation

The derivative of a constant is equal to 0

Basic Power Rule:

f(x) = cxⁿ
f’(x) = c·nxⁿ⁻¹

Product Rule: $\frac{d}{dx} [f(x)g(x)]=f'(x)g(x) + g'(x)f(x)$

Chain Rule: $\frac{d}{dx}[f(g(x))] =f'(g(x)) \cdot g'(x)$

Quotient Rule: $\frac{d}{dx} [\frac{f(x)}{g(x)} ]=\frac{g(x)f'(x)-g'(x)f(x)}{g^2(x)}$

Step-by-step explanation:

Step 1: Define

-y - 2x³ = y²

Rate of change of tangent line at point (-1, -2)

Step 2: Differentiate Pt. 1

Find 1st Derivative

Implicit Differentiation [Basic Power Rule]: $-y'-6x^2=2yy'$
[Algebra] Isolate y' terms: $-6x^2=2yy'+y'$
[Algebra] Factor y': $-6x^2=y'(2y+1)$
[Algebra] Isolate y': $\frac{-6x^2}{(2y+1)}=y'$
[Algebra] Rewrite: $y' = \frac{-6x^2}{(2y+1)}$

Step 3: Differentiate Pt. 2

Find 2nd Derivative

Differentiate [Quotient Rule/Basic Power Rule]: $y'' = \frac{-12x(2y+1)+6x^2(2y')}{(2y+1)^2}$
[Derivative] Simplify: $y'' = \frac{-24xy-12x+12x^2y'}{(2y+1)^2}$
[Derivative] Back-Substitute y': $y'' = \frac{-24xy-12x+12x^2(\frac{-6x^2}{2y+1} )}{(2y+1)^2}$
[Derivative] Simplify: $y'' = \frac{-24xy-12x-\frac{72x^4}{2y+1} }{(2y+1)^2}$

Step 4: Find Slope at Given Point

[Algebra] Substitute in x and y: $y''(-1,-2) = \frac{-24(-1)(-2)-12(-1)-\frac{72(-1)^4}{2(-2)+1} }{(2(-2)+1)^2}$
[Pre-Algebra] Exponents: $y''(-1,-2) = \frac{-24(-1)(-2)-12(-1)-\frac{72(1)}{2(-2)+1} }{(2(-2)+1)^2}$
[Pre-Algebra] Multiply: $y''(-1,-2) = \frac{-48+12-\frac{72}{-4+1} }{(-4+1)^2}$
[Pre-Algebra] Add: $y''(-1,-2) = \frac{-36-\frac{72}{-3} }{(-3)^2}$
[Pre-Algebra] Exponents: $y''(-1,-2) = \frac{-36-\frac{72}{-3} }{9}$
[Pre-Algebra] Divide: $y''(-1,-2) = \frac{-36+24 }{9}$
[Pre-Algebra] Add: $y''(-1,-2) = \frac{-12}{9}$
[Pre-Algebra] Simplify: $y''(-1,-2) = \frac{-4}{3}$

6 0

3 years ago

What is 1/10 of 6,000

guapka [62]

600 is your answer....

4 0

3 years ago

Read 2 more answers

What is the following product? sqrt 12*sqrt 18

uysha [10]

------------------
√12*√18

2√3√18

2√3 x 3√2

2 x 3√3 x 2

2 x 3√6

6√6 or 14.696938
------------------

6 0

3 years ago

Read 2 more answers

Sean has 3 times as many vegetable plants as Liz and Sejuan combined. Liz has 3 vegetable plants, and Sejuan has 2 vegetable pla

DIA [1.3K]

Let
x------------>Sean vegetable plants
y------------>Liz vegetable plants
z------------>Sejuan vegetable plants

we know that
y=3
z=2
x=3(y+z)--------> 3(3+2)=15

the answer part A) is
Sean has 15 vegetable plants

part B

This is an example of a part-whole problem.----------> true
This is an example of a comparison problem.-------> true
Addition then multiplication can be used to solve the problem.------> true

5 0

4 years ago