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musickatia [10]
3 years ago
11

i found 3 boxes of marker. each box had 10 markers inside.if i shared the markers i found 5 friendSs how many markers will each

person get
Mathematics
2 answers:
Strike441 [17]3 years ago
6 0
So, 3 boxes x 10 markers=
 
30 markers/ 5=

6 markers each person will get.
gregori [183]3 years ago
6 0
The answer is 6 because u do 3 times 10 equals 30 then divide 30 by 5 and that equals 6
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your team wins 18 medals at a track meet the medals are gold silver and bronze in ratio of 2;2;5. how many of each medal were wo
WITCHER [35]

The team won 4 gold medals, 4 silver medals and 10 bronze medals.

Step-by-step explanation:

Given,

Total medals won = 18

Ratio of gold, silver and bronze = 2:2:5

Let,

x be the original number.

Therefore,

Gold medals = 2x

Silver medals = 2x

Bronze medals = 5x

According to given statement;

2x+2x+5x=18\\9x=18

Dividing both sides by 9

\frac{9x}{9}=\frac{18}{9}\\x=2

Gold medals = 2x = 2(2) = 4

Silver medals = 2x = 2(2) = 4

Bronze medals = 5x = 5(2) = 10

The team won 4 gold medals, 4 silver medals and 10 bronze medals.

Keywords: ratio, division

Learn more about division at:

  • brainly.com/question/1626495
  • brainly.com/question/1626676

#LearnwithBrainly

8 0
4 years ago
WILL GIVE BRAINLIEST AND 20 PTS
exis [7]

Answer:16

Step-by-step explanation:dsbwdb

5 0
3 years ago
Find dy/dx by implicit differentiation for ysin(y) = xcos(x)
tatyana61 [14]

Answer:

\frac{dy}{dx}=\frac{\cos(x)-x\sin(x)}{\sin(y)+y\cos(y)}

Step-by-step explanation:

So we have:

y\sin(y)=x\cos(x)

And we want to find dy/dx.

So, let's take the derivative of both sides with respect to x:

\frac{d}{dx}[y\sin(y)]=\frac{d}{dx}[x\cos(x)]

Let's do each side individually.

Left Side:

We have:

\frac{d}{dx}[y\sin(y)]

We can use the product rule:

(uv)'=u'v+uv'

So, our derivative is:

=\frac{d}{dx}[y]\sin(y)+y\frac{d}{dx}[\sin(y)]

We must implicitly differentiate for y. This gives us:

=\frac{dy}{dx}\sin(y)+y\frac{d}{dx}[\sin(y)]

For the sin(y), we need to use the chain rule:

u(v(x))'=u'(v(x))\cdot v'(x)

Our u(x) is sin(x) and our v(x) is y. So, u'(x) is cos(x) and v'(x) is dy/dx.

So, our derivative is:

=\frac{dy}{dx}\sin(y)+y(\cos(y)\cdot\frac{dy}{dx}})

Simplify:

=\frac{dy}{dx}\sin(y)+y\cos(y)\cdot\frac{dy}{dx}}

And we are done for the right.

Right Side:

We have:

\frac{d}{dx}[x\cos(x)]

This will be significantly easier since it's just x like normal.

Again, let's use the product rule:

=\frac{d}{dx}[x]\cos(x)+x\frac{d}{dx}[\cos(x)]

Differentiate:

=\cos(x)-x\sin(x)

So, our entire equation is:

=\frac{dy}{dx}\sin(y)+y\cos(y)\cdot\frac{dy}{dx}}=\cos(x)-x\sin(x)

To find our derivative, we need to solve for dy/dx. So, let's factor out a dy/dx from the left. This yields:

\frac{dy}{dx}(\sin(y)+y\cos(y))=\cos(x)-x\sin(x)

Finally, divide everything by the expression inside the parentheses to obtain our derivative:

\frac{dy}{dx}=\frac{\cos(x)-x\sin(x)}{\sin(y)+y\cos(y)}

And we're done!

5 0
3 years ago
Which of the following equations best represents the graph of a function f(m)?
Inessa [10]

Answer: y = f(m)


Justification:


By definition, the graph of a function in the cartesian coordinate plane is the plot of the curve that join all the points that satisfy the equation of the function.


In the cartesian coordinate plane, each point is represented by a pair of coordinates (y, x). y is the value of the function f(x), and x is any input value of the function.


In this case, the function is given as f(m), which means that the input value is represented by m.


Hence, the graph is the plot of y = f(m).


The choice of the letter used for the variable is completely arbitrary and does not change either the math or the graph. It could have been said that the function is f(x) in which case the graph would be y = f(x). Nothing changes but the name that you use.

4 0
3 years ago
Jane evaluates x squared minus 3 x + 5 for x = negative 2 below. Step 1: (negative 2) squared minus 3 (negative 2) + 5 Step 2: E
rjkz [21]

Answer:

Kindly check explanation

Step-by-step explanation:

Given the question :

Jane evaluates x squared minus 3 x + 5 for x = negative 2 below. Step 1: (negative 2) squared minus 3 (negative 2) + 5 Step 2: Equals negative 4 + 6 + 5 Step 3: Equals 7 What, if any, was Jane's mistake?

Jane's evaluation :

x² - 3x + 5 for x = - 2

Step 1:

(-2)² - 3(-2) + 5

Step 2:

-4 + 6 + 5

Step 3 :

= 7

Jane's mistake was in STEP2,

evaluating (-2)² = 4 and not - 4

Hence, (-2)² - 3(-2) + 5

= 4 + 6 + 5

= 15

4 0
3 years ago
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