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Nina [5.8K]
3 years ago
8

To help where it saysFoston is between

Mathematics
1 answer:
Svetlanka [38]3 years ago
7 0
It says from liberty to West Quall it is 6in, and from Froston to Liberty is 4in. So:
6 - 4 = 2 inches
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The given line passes through the points (-2,-4) and (2,2) What is the equation, in point-slope form, of the line that is parall
Morgarella [4.7K]

Answer:

(y-1)=\frac{3}{2}(x+3)


Step-by-step explanation:

The point slope form of a line is (y-y_1)=m(x-x_1) where x_1=-3\\y_1=1. We write  

(y-1)=m(x--3)\\(y-1)=m(x+3)


Since the line is parallel to the line shown it will have the same slope. To find m, count the slope from each marked point on the graph. Count the rise then the run and create a fraction rise/run. The slope is 6/4 which simplifies to 3/2. Now substitute it for m.

(y-1)=\frac{3}{2}(x+3)




3 0
4 years ago
Ms. Johnson owns a cabinet business that installs cabinets in kitchens. Her employees can install 2/3 of a kitchen cabinet set i
dmitriy555 [2]

Answer:

I don't know

Step-by-step explanation:

hi

8 0
3 years ago
Find the <br> Range 19,6,8,10,8
frosja888 [35]

Answer:

13

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
What would this equal too look at the screen shot
jekas [21]

Given:

The figure of two parallel lines MP and QS.

A transversal line KL interests the two parallel lines.

m\angle KNM =146^\circ

To find:

The m\angle KRQ.

Solution:

If a transversal line intersect the two parallel lines, then the corresponding angles are congruent and their measures are equal.

In the given figure \angle KRQ and \angle KNM corresponding angles. It means their measures are equal.

m\angle KRQ=m\angle KNM

m\angle KRQ=146^\circ

Therefore, m\angle KRQ=146^\circ.

6 0
3 years ago
Una avenida está siendo asfaltada por etapas. En la primera etapa se asfaltó la mitad; en la segunda, la quinta parte, y en la t
s344n2d4d5 [400]

Answer:

Sabemos que:

L es el largo de la avenida.

En la primer etapa se asfalto la mitad, L/2, entonces lo que queda por asfaltar es:

L - L/2 = L/2.

En la segunda etapa se asfalto la quinta parte, L/5, entonces lo que queda por asfaltar es:

L/2 - L/5 = 5*L/10 - 2*L/10 = (3/10)*L

En la tercer etapa se asfalto la cuarta parte del total, L/4, entonces lo que queda por asfaltar es:

(3/10)*L - L/4 = 12*L/40 - 10L/40 = (2/40)*L

Y sabemos que este ultimo pedazo que queda por asfaltar es de 200m:

(2/40)*L = 200m

L = 200m*(40/2) = 4,000m

7 0
3 years ago
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