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Airida [17]
3 years ago
10

Find an equation of the circle that has center (-6,2) and passes through (1,-2).

Mathematics
2 answers:
Natali5045456 [20]3 years ago
8 0

Answer:

(x+6)^2+(y-2)^2=65

Step-by-step explanation:

Rzqust [24]3 years ago
3 0

Answer:

Should be (x+6)^2+(y-2)^2=65

the number after the carrot represents an exponent

hope it helps

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Correct Answers only please!
Tcecarenko [31]

Answer:

C. $97

Step-by-step explanation:

The average of his wage for all 15 days is the sum of all wages for the 15 days divided by 15.

average wage for 15 days = (sum of wages for the 15 days)/15

The amount of wages during a number of days is the product of the average wage of those days and the number of days.

First 7 days:

average wage: $87

number of days: 7

total wages in first 7 days = 7 * $87/day = $609

Last 7 days:

average wage: $92

number of days: 7

total wages in last 7 days = 7 * $92/day = $644

8th day:

wages of the 8th day is unknown, so we let x = wages of the 8th day

total wages of 15 days = (wages of first 7 days) + (wages of 8th day) + (wages of last 7 days)

total wages of 15 days = 609 + x + 644 = x + 1253

average wage for 15 days = (sum of wages for the 15 days)/15

average wage for 15 days = (x + 1253)/15

We are told the average for the 15 days is $90/day.

(x + 1253)/15 = 90

Multiply both sides by 15.

x + 1253 = 1350

Subtract 1253 from both sides.

x = 97

Answer: $97

3 0
3 years ago
Can someone show me at least trial one
GenaCL600 [577]
Pick a number: 5
Add 7: 5+7=12
Triple the result: 12*12*12=1728
Add 9= 1728+9=1737
Divide by 3 = 1737/3=579
Subtract original number = 579-5=574

Now pick a different number a do the same process

Hope that helps
8 0
3 years ago
Read 2 more answers
Given h(x) = x^2-4/2, find h(-8)
vlada-n [284]

Answer:

62

Step-by-step explanation:

(-8)^2-2

64-2 = 62

7 0
3 years ago
4x + 6 < 3x − 5 I have to solve the inequality please help
garik1379 [7]

Answer:

x < -11 or x ∈ (-∞, -11)

Step-by-step explanation:

4x + 6 < 3x - 5

<=> 4x - 3x < -5 - 6

<=> x < -11

7 0
3 years ago
Read 2 more answers
Determine the point of intersection of right bisectors in a triangle ∆ with vertices A (-3, 5), B (1, 1) and (−7, −3). Find the
iris [78.8K]

Answer:

Point of intersection (-11/3 , 1/3)

All distances from the vertices are \frac{10\sqrt{2} }{3}

Step-by-step explanation:

The vertices of the triangle is A(-3,5) , B (1,1) and C (-7,-3)

We need to find the perpendicular bisector of the triangle first

let's take one side connecting A and B

mid point of A and B = (-1,3)

Slope of the line joining A and B = -1

slope of perpendicular to line joining A and B = 1

equation of line passing through (-1,3) with slope 1

y - 3 = 1(x-(-1))

y -3 = x+1

x-y = -4 ............(1)

similarly

mid point joining B and C = (-3,-1)

slope perpendicular to line joining B and C  =  -2

Equation of perpendicular bisector of line joining B and C =

y +1 = -2(x +3 )

y+1 = -2x -6

2x+y = -7 ..........(2)

On solving 1 and 2

x= -11/3 , y= 1/3

Distances

From A = \frac{10\sqrt{2} }{3}

From B = \frac{10\sqrt{2} }{3}

From C = \frac{10\sqrt{2} }{3}

7 0
2 years ago
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