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Airida [17]
3 years ago
10

Find an equation of the circle that has center (-6,2) and passes through (1,-2).

Mathematics
2 answers:
Natali5045456 [20]3 years ago
8 0

Answer:

(x+6)^2+(y-2)^2=65

Step-by-step explanation:

Rzqust [24]3 years ago
3 0

Answer:

Should be (x+6)^2+(y-2)^2=65

the number after the carrot represents an exponent

hope it helps

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Find the measure of angle A
otez555 [7]

Answer:

<A=35

Step-by-step explanation:

70+x+79+x+39=180

2x+188=180

2x=-8

x=-8/2 or -4

<A=x+39

<A=-4+39

<A=35

7 0
3 years ago
at the pet fair,darlene's dog weighed 5 times as much as leah's dog.together the dog weighed 84 pounds. how much did each dog we
Sati [7]
It is 420 because your doing 5 x 84
5 0
4 years ago
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There are 21 more green crayons than blue crayons. There are 14 blue crayons. How many green crayons are there?
dimaraw [331]

Answer:

35 green crayons

Step-by-step explanation:

g is number of green crayons

b is number of blue crayons

g = b + 21

plug in 14 for b:

g = 14 + 21

g = 35

35 green crayons

3 0
3 years ago
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Please solve this for me!!!!
IRINA_888 [86]
323 because I did the quiz and got it right txt me if you need help
6 0
3 years ago
A company that produces fine crystal knows from experience that 17% of its goblets have cosmetic flaws and must be classified as
Alex73 [517]

Answer:

0.3891 = 38.91% probability that only one is a second

Step-by-step explanation:

For each globet, there are only two possible outcoes. Either they have cosmetic flaws, or they do not. The probability of a goblet having a cosmetic flaw is independent of other globets. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

17% of its goblets have cosmetic flaws and must be classified as "seconds."

This means that p = 0.17

Among seven randomly selected goblets, how likely is it that only one is a second

This is P(X = 1) when n = 7. So

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 1) = C_{7,1}.(0.17)^{1}.(0.83)^{6} = 0.3891

0.3891 = 38.91% probability that only one is a second

7 0
3 years ago
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