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Airida [17]
2 years ago
10

Find an equation of the circle that has center (-6,2) and passes through (1,-2).

Mathematics
2 answers:
Natali5045456 [20]2 years ago
8 0

Answer:

(x+6)^2+(y-2)^2=65

Step-by-step explanation:

Rzqust [24]2 years ago
3 0

Answer:

Should be (x+6)^2+(y-2)^2=65

the number after the carrot represents an exponent

hope it helps

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What is the solution to the system? <br><br> (___,___)
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For the first line we have a slope of (y2-y1)/(x2-x1)

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The solution occurs when both the x and y coordinates for each are equal, so we can say y=y, and use our two line equations...

2x=(-3x+14)/2

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(2,4)


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2 years ago
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1. 5%

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