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Travka [436]
3 years ago
12

Calculate the monthly payment for a $10,000 auto loan over three years at 5% annual interest.

Mathematics
1 answer:
zhenek [66]3 years ago
4 0

Answer:

Step-by-step explanation:

A

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2. Is the data set "dollars of sales per week” quantitative or qualitative?
Ipatiy [6.2K]

Answer:

this would be quantitative.

Step-by-step explanation:

because its an amount like dollars of sales per week so it would be quantitative or numbers

4 0
3 years ago
Two cars traveled equal distances in different amounts of time. Car A traveled the distance in 2 h, and Car B traveled the dista
scZoUnD [109]
The answer to this question 
is 60mph 

3 0
3 years ago
20 Points:
belka [17]

Answer:

D. 105 students and 150 guests

Step-by-step explanation:

105 students and $1 for each ticket is $105.(105 x 1 = 105)

150 guests and $5 for each ticket is $750.(150 x 5 =750)

$105 + $750 = $855

6 0
2 years ago
Read 2 more answers
Write an equation of the line satisfying the given conditions. Through (2, -5), parallel to 5x 6y + 7
mojhsa [17]

We have to determine the equation of the line passing through the point (2,-5) and parallel to the line 5x = 6y+7

When two lines are parallel, then the slopes of the two lines are equal.

Equation of line with point (x_1, y_1) and slope 'm' is given by:

(y-y_1) = m(x-x_1)

Since, we have to determine the equation of a line with point (2,-5).

So, the equation of the line is : (y-(-5)) = m(x-2)

y+5 = m(x-2)

Since, the line is parallel to the line 5x = 6y+ 7

So, 6y +7 = 5x

6y = 5x - 7

y = \frac{5}{6}x - \frac{7}{6}

So, slope of the line  'm' is \frac{5}{6}.

Therefore, the equation of the line is:

(y+5) = \frac{5}{6}(x-2)

6y + 30 = 5x - 10

6y - 5x = -10-30

6y - 5x = -40

Therefore, 6y - 5x = -40 is the required equation of the line.

8 0
3 years ago
Consider the initial value problem y′′+36y=2cos(6t),y(0)=0,y′(0)=0. y″+36y=2cos⁡(6t),y(0)=0,y′(0)=0. Take the Laplace transform
Bingel [31]

Recall the Laplace transform of a second-order derivative,

L(y''(t)) = s^2Y(s)-sy(0)-y'(0)

and the transform of cosine,

L(\cos(at))=\dfrac s{a^2+s^2}

Here, both y(0)=y'(0)=0, so taking the transform of both sides of

y''(t)+36y(t)=2\cos(6t)

gives

s^2Y(s)+36Y(s)=\dfrac{2s}{36+s^2}

\implies Y(s)=\dfrac{2s}{(s^2+36)^2}

4 0
3 years ago
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