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Tanzania [10]
3 years ago
5

4√(-81)+6√(-36) (simplify your answer))

Mathematics
1 answer:
Lapatulllka [165]3 years ago
3 0
When looking at expressions like this,, you need to remember that the square root of a negative number does not exist in the set of Real Numbers. This means that there is no way to simplify this expression,, making the correct answer to your question Undefined.
Let me know if you have any further questions.
:)
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Simple equation with division that equals 8
Nitella [24]

Answer:

64 divided by 8

Step-by-step explanation:

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3 years ago
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Simplify [2 × (10 5)] - 5 Question 4 options: 25 20 12.5 120
frez [133]

what is the symbol between 10 and 5


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Jayden and Sheridan both tried to find the missing side of the right triangle. A right triangle is shown. One leg is labeled as
stellarik [79]

Answer:

Sheridan's Work is correct

Step-by-step explanation:

we know that

The lengths side of a right triangle must satisfy the Pythagoras Theorem

c^{2}=a^{2}+b^{2}

where

a and b are the legs

c is the hypotenuse (the greater side)

In this problem

Let

a=7\ cm\\c=13\ cm

substitute

13^{2}=7^{2}+b^{2}

Solve for b

169=49+b^{2}

b^{2}=169-49

b^{2}=120

b=\sqrt{120}\ cm

b=10.95\ cm

we have that

<em>Jayden's Work</em>

a^{2}+b^{2}=c^{2}

a=7\ cm\\b=13\ cm

substitute and solve for c

7^{2}+13^{2}=c^{2}

49+169=c^{2}

218=c^{2}

c=\sqrt{218}\ cm

c=14.76\ cm

Jayden's Work is incorrect, because the missing side is not the hypotenuse of the right triangle

<em>Sheridan's Work</em>

a^{2}+b^{2}=c^{2}

a=7\ cm\\c=13\ cm

substitute

7^{2}+b^{2}=13^{2}

Solve for b

49+b^{2}=169

b^{2}=169-49

b^{2}=120

b=\sqrt{120}\ cm

b=10.95\ cm

therefore

Sheridan's Work is correct

6 0
3 years ago
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Digiron [165]

Answer:

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Step-by-step explanation:

0.13*20=2.6g

2.6g=2600mg

7 0
2 years ago
Jose purchased 4/9 pound of peanut and 7/11 pounds of raisins find the total weight of his purchase
azamat

Answer:

The total weight of his purchase is 1.08 pounds

Step-by-step explanation:

To find the total weight of his purchase, we sum the weight of each of his purchases.

He purchased:

4/9 pound of peanut.

7/11 pounds of raisins

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The least common multiple between 9 and 11 is 99.

Then

\frac{4}{9} + \frac{7}{11} = \frac{11*4 + 9*7}{99} = \frac{107}{99} = 1.08

The total weight of his purchase is 1.08 pounds

8 0
3 years ago
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