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2 years ago

How do I solve This I need help

Mathematics

1 answer:

Delvig [45]2 years ago

6 0

So we have:

xk = v + w solve for x
divide both sides by k to isolate the variable x:

x = (v+w)/k

^^This is your answer!

Hope I helped!

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sound travels 1,500 m/s through water at 25 degrees celciesunder these conditions how long would it take to travel 300m

Fantom [35]

Answer: it would take 18,00 M/S

Step-by-step explanation:

First you have to fined the unit rate

1,500/25= 60

Now your gonna do

300x60= 18,00

3 0

2 years ago

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Juan cuts a piece of paper in half. he then cuts each half into thirds and each of those pieces into eights. finally, he cuts ea

Nookie1986 [14]

Answer:

D: 768

Step-by-step explanation:

First, he divides a piece of paper in half.

$1 \div \frac{1}{2} = 2$

He gets two pieces.

Next, he cuts each of the pieces into three parts.

$2 \div \frac{1}{3} = 6$

Thirdly, he cuts each of the 6 pieces into 8 pieces.

$6 \div \frac{1}{8} = 48$

Lastly, he divides each piece into 16 parts.

$48 \div \frac{1}{16} = 768$

He has 768 pieces in the end. (D)

7 0

3 years ago

The ratio of 6th graders to 7th graders in a MATHCOUNTS club is 5:4. The ratio of 8th graders to 7th graders in the same club is

lorasvet [3.4K]

ANSWER
========

Ratio of 8th graders to 7th graders = 3 : 2

Let the number of graders be 3x and 2x

Number of 8th graders = 18

So , 3x = 18

x = 18/3 = 6

Number of 7th graders = 2 × 6 = 12

Ratio of 6th graders to 7th graders = 5 : 4

Let the number of graders be 5a and 4a

Number of 7th graders = 12

So , 4a = 12

a = 12/4 = 3

Number of 6th graders = 5×3 = 15 ANS

_______________________________

#BE BRAINLY

3 0

2 years ago

Read 2 more answers

Please someone help me

irina1246 [14]

The area of the triangle extension is 12, because the total side length it is on is 18, and the segments to the sides of the triangle are 6 each, meaning 18-12=6, the height of the triangle. The base is given as 4, so 1/2(4x6)=24/2=12.

Add this to the area of the rectangle, 9x18=162, and 162+12=174.

The area is 174.

7 0

3 years ago

Read 2 more answers

The angle θ 1 is located in Quadrant IV, and cos ⁡ ( θ 1 ) = 9/ 19 , theta, start subscript, 1, end subscript, right parenthesis

Firdavs [7]

Answer:

$sin\theta_1 = - \frac{2\sqrt{70}}{19}$

Step-by-step explanation:

We are given that $\theta_1$ is in <em>fourth</em> quadrant.

$cos\theta_1$ is always positive in 4th quadrant and

$sin\theta_1$ is always negative in 4th quadrant.

Also, we know the following identity about $sin\theta$ and $cos\theta$ :

$sin^2\theta + cos^2\theta = 1$

Using \theta_1 in place of \theta:

$sin^2\theta_1 + cos^2\theta_1 = 1$

We are given that $cos\theta_1 = \frac{9}{19}$

$\Rightarrow sin^2\theta_1 + \dfrac{9^2}{19^2} = 1\\\Rightarrow sin^2\theta_1 = 1 - \dfrac{81}{361}\\\Rightarrow sin^2\theta_1 = \dfrac{361-81}{361}\\\Rightarrow sin^2\theta_1 = \dfrac{280}{361}\\\Rightarrow sin\theta_1 = \sqrt{\dfrac{280}{361}}\\\Rightarrow sin\theta_1 = +\dfrac{2\sqrt{70}}{19}, -\dfrac{2\sqrt{70}}{19}$

$\theta_1$ is in <em>4th quadrant </em>so $sin\theta_1$ is negative.

So, value of $sin\theta_1 = - \frac{2\sqrt{70}}{19}$

6 0

2 years ago