65 sequences.
Lets solve the problem,
The last term is 0.
To form the first 18 terms, we must combine the following two sequences:
0-1 and 0-1-1
Any combination of these two sequences will yield a valid case in which no two 0's and no three 1's are adjacent
So we will combine identical 2-term sequences with identical 3-term sequences to yield a total of 18 terms, we get:
2x + 3y = 18
Case 1: x=9 and y=0
Number of ways to arrange 9 identical 2-term sequences = 1
Case 2: x=6 and y=2
Number of ways to arrange 6 identical 2-term sequences and 2 identical 3-term sequences =8!6!2!=28=8!6!2!=28
Case 3: x=3 and y=4
Number of ways to arrange 3 identical 2-term sequences and 4 identical 3-term sequences =7!3!4!=35=7!3!4!=35
Case 4: x=0 and y=6
Number of ways to arrange 6 identical 3-term sequences = 1
Total ways = Case 1 + Case 2 + Case 3 + Case 4 = 1 + 28 + 35 + 1 = 65
Hence the number of sequences are 65.
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Answer :
y=3/4x-6
explanation:
it is already in standard form.
Answer:
I can't draw a picture but its possible cuz they painted ABOUT 1/5 of the bird house so Jane could have painted a bit more than 1/5 but it would still be about 1/5
Answer:
Step-by-step explanation:
Given
x² - 3x
To make the expression a perfect square
add ( half the coefficient of the x- term )²
x² + 2( - 
)x + , thus
x² - 3x +
= (x - )² ← a perfect square
