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Bezzdna [24]
3 years ago
8

MULTIPLE CHOICE, PLS HELP!!

Mathematics
1 answer:
bixtya [17]3 years ago
4 0

We know that : Sin²θ + Cos²θ = 1

Given : Sinθ \bf{= \frac{4}{7}}

\bf{\implies (\frac{4}{7})^2 + Cos^2(\theta) = 1}

\bf{\implies Cos^2(\theta) = 1 - \frac{16}{49}}

\bf{\implies Cos^2(\theta) =(\frac{49 - 16}{49})}

\bf{\implies Cos^2(\theta) =(\frac{33}{49})}

\bf{\implies Cos(\theta) = (\pm)(\frac{\sqrt{33}}{7})}

Given : θ lies in Quadrant II

We know that : Cosθ is Negative in Quadrant II

\bf{\implies Cos(\theta) = (-)(\frac{\sqrt{33}}{7})}

Option 3 is the Answer

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