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dmitriy555 [2]
3 years ago
8

When the level of confidence and the sample size remain the same, a confidence interval for a population mean μ will be ________

________ when the sample standard deviation s is small than when s is large?
Mathematics
1 answer:
nikdorinn [45]3 years ago
3 0
...will be WIDER when the...
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If a rectangle has a length of 4 square root of 2 and a width of 7 square root of 18 what
Orlov [11]

Answer:8^4 + 14^36 is the perimeter because they are for sides in a rectangle so you have to double the amount.

7 0
3 years ago
On which graph does the red point have a clear meaning?
Kobotan [32]

Answer:

The graph where the red point has a meaning is the graph C or third graph.

Step-by-step explanation:

As we can see the first and second graphs are irrelevant and have no relation between the x axis and y axis.

In graph A, the bird feeder graph is shown where the quart is a unit for liquids and pounds is a unit for solids. Thus, the red point cannot be defined.

Similarly, in graph B, height and team numbers are not related to each other in any way, so not clear meaning can be withdrawn here,

In graph C, the relation between cost of pictures and number of pictures are shown. We can very well understand here, that as the number of pictures increases, the cost increases.

So, the graph where the red point has a meaning is the graph C or third graph.

4 0
3 years ago
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A wire b units long is cut into two pieces. One piece is bent into an equilateral triangle and the other is bent into a circle.
mezya [45]
1. Divide wire b in parts x and b-x. 

2. Bend the b-x piece to form a triangle with side (b-x)/3

There are many ways to find the area of the equilateral triangle. One is by the formula A= \frac{1}{2}sin60^{o}side*side=   \frac{1}{2} \frac{ \sqrt{3} }{2}  (\frac{b-x}{3}) ^{2}= \frac{ \sqrt{3} }{36}(b-x)^{2}
A=\frac{ \sqrt{3} }{36}(b-x)^{2}=\frac{ \sqrt{3} }{36}( b^{2}-2bx+ x^{2}  )=\frac{ \sqrt{3} }{36}b^{2}-\frac{ \sqrt{3} }{18}bx+ \frac{ \sqrt{3} }{36}x^{2}

Another way is apply the formula A=1/2*base*altitude,
where the altitude can be found by applying the pythagorean theorem on the triangle with hypothenuse (b-x)/3 and side (b-x)/6

3. Let x be the circumference of the circle.

 2 \pi r=x

so r= \frac{x}{2 \pi }

Area of circle = \pi  r^{2}= \pi  ( \frac{x}{2 \pi } )^{2} = \frac{ \pi }{ 4 \pi ^{2}  }* x^{2} = \frac{1}{4 \pi } x^{2}

4. Let f(x)=\frac{ \sqrt{3} }{36}b^{2}-\frac{ \sqrt{3} }{18}bx+ \frac{ \sqrt{3} }{36}x^{2}+\frac{1}{4 \pi } x^{2}

be the function of the sum of the areas of the triangle and circle.

5. f(x) is a minimum means f'(x)=0

f'(x)=\frac{ -\sqrt{3} }{18}b+ \frac{ \sqrt{3} }{18}x+\frac{1}{2 \pi } x=0

\frac{ -\sqrt{3} }{18}b+ \frac{ \sqrt{3} }{18}x+\frac{1}{2 \pi } x=0

(\frac{ \sqrt{3} }{18}+\frac{1}{2 \pi }) x=\frac{ \sqrt{3} }{18}b

x= \frac{\frac{ \sqrt{3} }{18}b}{(\frac{ \sqrt{3} }{18}+\frac{1}{2 \pi }) }

6. So one part is \frac{\frac{ \sqrt{3} }{18}b}{(\frac{ \sqrt{3} }{18}+\frac{1}{2 \pi }) } and the other part is b-\frac{\frac{ \sqrt{3} }{18}b}{(\frac{ \sqrt{3} }{18}+\frac{1}{2 \pi }) }

4 0
3 years ago
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A deli sells sliced meat and cheese. One customer purchases 4 pounds of meat and 5 pounds of cheese for a total of $30.50. A san
Elenna [48]

Answer:x=cost per pound of meat

Y=Cost per pound of cheese

The deli charges 4.50 for a pound of meat

Step-by-step explanation:

4 0
3 years ago
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What is 9 times 9<br> It’s so hard
steposvetlana [31]
9x9 is 81 and yes its very hard haha
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