Find the velocity first, the "slope".
m=(y2-y1)/(x2-x1)
m=(95.5-53)/(4-2)
m=21.25 ? Your equations are wrong, I'll double check with another set of points...
m=(350.5-308)/(16-14)
m=21.25 LOL, yep none of your lines has the correct slope.
Anyway...
y=21.25x+b, using any point we can solve for the y-intercept, or "b", (2, 53)
53=21.25(2)+b
53=42.5+b
10.5=b so the distance to the lighthouse as a function of time is:
y=21.25x+10.5
So essentially, you should fire your teacher or burn that book you are using :)
The answer to the question is 52
Answer:
−135z
2
−2z
The 2 is representing Square
Step-by-step explanation:
(3z)
2
−4z+11−(12z)
2
+2z−11
Expand (3z)
2
.
3
2
z
2
−4z+11−(12z)
2
+2z−11
Calculate 3 to the power of 2 and get 9.
9z
2
−4z+11−(12z)
2
+2z−11
Expand (12z)
2
.
9z
2
−4z+11−12
2
z
2
+2z−11
Calculate 12 to the power of 2 and get 144.
9z
2
−4z+11−144z
2
+2z−11
Combine 9z
2
and −144z
2
to get −135z
2
.
−135z
2
−4z+11+2z−11
Combine −4z and 2z to get −2z.
−135z
2
−2z+11−11
Subtract 11 from 11 to get 0.
−135z
2
−2z
20 * (31/100) = 21*0.31=6.51
20.00-6.51=13.49
Caleb paid $13.49
