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timofeeve [1]
3 years ago
8

For the following exercises, find the equation of the line using given information (1, 7) and (3, 7)

Mathematics
1 answer:
arlik [135]3 years ago
6 0

y = 7

Horizontal line, therefore has a slope of zero

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Which of these is not an equation
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Which point satisfies the system of equations y= 3x - 2 and y=-2x + 3?
monitta

Answer:

The points which satisfy the given lines is ( 1 , 1 )  

Step-by-step explanation:

Given as :

The equation of lines is

y = 3 x - 2         ........    1  And

y = - 2 x + 3      ........ 2

From equation given

3 x - 2 = - 2 x + 3

Or , 3 x + 2 x = 3 +2

Or,   5 x = 5

So ,     x = \frac{5}{5} = 1

Put the value of x in eq 1

So, y = 3 ( 1 ) - 2

Or, y = 3 - 2 = 1

∴,  the points ( x , y ) = ( 1 , 1 )

Hence The points which satisfy the given lines is ( 1 , 1 )  Answer

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3 years ago
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Answer:

31.4 in

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C = π(10 in) = 10π in, or roughly 31.4 in.

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3 years ago
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Read 2 more answers
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Well,  since we know is a geometric sequence, we can always get the common ratio  of it by simply dividing one value by the one behind it... so let's do so, with say hmm -32 and 8  -32/8 = -4  <-- our common ratio

the first term is -2

\bf n^{th}\textit{ term of a geometric sequence}\\\\&#10;a_n=a_1\cdot r^{n-1}\qquad &#10;\begin{cases}&#10;n=n^{th}\ term\\&#10;a_1=\textit{first term's value}\\&#10;r=\textit{common ratio}\\&#10;----------\\&#10;a_1=-2\\&#10;r=-4&#10;\end{cases}\implies a_n=-2(-4)^{n-1}
4 0
3 years ago
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