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kirill [66]
3 years ago
10

40Points? CORRECT answer please

Mathematics
1 answer:
irina [24]3 years ago
3 0

Answer:

<h2>f(-2) = 12.5</h2>

Step-by-step explanation:

f(t)=2(0.4)^t

f(-2) → put t = -2 to the equation of the function:

f(-2)=2(0.4)^{-2}=2\left(\dfrac{4}{10}\right)^{-2}=2\left(\dfrac{2}{5}\right)^{-2}

Use a^{-n}=\left(\dfrac{1}{a}\right)^n

f(-2)=2\left(\dfrac{5}{2}\right)^2=2\left(\dfrac{25}{4}\right)=\dfrac{25}{2}=12.5

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Step-by-step explanation: they are lines that form a right angle

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How do you do this problem? I need to know how you found the answer.
Alexxandr [17]

to get the equation of a line, we simply need two points, say for the Red one ... notice in the graph the lines passes through (0,2) and (-1,6), so let's use those


\bf (\stackrel{x_1}{0}~,~\stackrel{y_1}{2})\qquad (\stackrel{x_2}{-1}~,~\stackrel{y_2}{6}) \\\\\\ slope = m\implies \cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{6-2}{-1-0}\implies \cfrac{4}{-1}\implies -4 \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-2=-4(x-0) \\\\\\ y-2=-4x\implies \blacktriangleright y=-4x+2 \blacktriangleleft


now, for the Blue one, say let's use hmmm it passes through (0,2) and (1.6)


\bf (\stackrel{x_1}{0}~,~\stackrel{y_1}{2})\qquad (\stackrel{x_2}{1}~,~\stackrel{y_2}{6}) \\\\\\ slope = m\implies \cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{6-2}{1-0}\implies \cfrac{4}{1}\implies 4 \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-2=4(x-0) \\\\\\ y-2=4x\implies \blacktriangleright y=4x+2 \blacktriangleleft

3 0
3 years ago
Solve the solution. How many solutions does it have? 4(2x-3)=2(4x-6)
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4(2x-3)=2(4x-6)

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7 0
4 years ago
Am I'm correct I linked a picture with it​
WARRIOR [948]

Answer: B

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Use the <u>Triangle Theorem.</u>

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Add the given components.

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