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zaharov [31]
3 years ago
11

HELP ME PLEASEEEEEEEEEEEEEEEE

Mathematics
1 answer:
mojhsa [17]3 years ago
7 0

Answer:

76

Step-by-step explanation:

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What is -7/12 + 7/10
KiRa [710]
0.1 or 0.16(000000000000000000000)
7 0
3 years ago
Read 2 more answers
1/2×(6×4)÷3+2 WORK AND ANSWER
Studentka2010 [4]

Answer:

½×(6×4). ÷3+2

½×24

=12÷3. +2

4+2

=6

7 0
2 years ago
PLEASE HELP ME I WILL MARK CORRECT ANSWER BRAINLIEST
Assoli18 [71]

Answer:

36 units

Step-by-step explanation:

to do this you must first find the lengths of all the sides with pythagorean theorem

for a to b you use

3^2 + 4^2 = c^2

9 + 16 = c^2

25 = c^2

c = 5

5 is one of the lengths

b to c uses the same equation

so

5 is another one of the lengths

for d to c your equation is

5^2 + 12^2 = c^2

25 + 144 = c^2

169 = c^2

13 is another of the lengths

d to a has the same length as c to d so there is another 13 unit length

so

5 + 5 + 13 + 13 is your equation to find the perimeter

5 + 5 + 13 + 13 = 36

that is your answer

6 0
2 years ago
The equation of the line
hammer [34]
(9,0) (0,9) choose any two points since it’s a straight line honey and the dk the difference between the two points

9-0
———. = 1
0-9
5 0
3 years ago
A researcher wants to determine whether the number of minutes adults spend online per day is related to gender. A random sample
suter [353]

Answer:

The expected frequency for the cell E2,2 is = 33

Step-by-step explanation:

The given data is

Gender               | 0-30| 30-60| 60-90| 90+       Totals

Male                    | 23    |    35   |   76    |  46        180

<u> Female               |   31   |    42   |   46    |  16         135    </u>

<u>Totals                    54         77        122    62          315  </u>

<u />

The expected frequency for the cell E2,2 is :

Expected for the (30-60 box for females)   =  Total of (30-6)/ (total )* females

                                                                      = ( 77/315)135= 33

Here p= 77/315 and n= 135

therefor X= pn = 33

χ²=  (33-42)²/33= 2.455  ( for the single value of E2,2=33)

Expected for the (30-60 box for males)   =  Total of (30-6)/ (total )* males

                                                                      = ( 77/315)180= 44

χ²=  (44-42)²/44= 0.09

The critical region is  χ² (0.05) 3 ≥  χ²= 11.34

Let the null and alternate hypothesis be

H0:the number of minutes spent online per day is not related to gender

against

Ha: the number of minutes spent online per day is related to gender

The single value of χ² for E2,2 = 2.45 is less than the critical value of 11.34.  

6 0
3 years ago
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