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2 years ago

In the picture down below

Mathematics

1 answer:

Nady [450]2 years ago

4 0

Answer:

Step-by-step explanation:

The answer is b because we are looking for opposites

The opposite of +x is -x

While the opposite of -3 is +3

with this, we can switch them around.

this gives us the inverse of 3-x

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A boxcar has the dimensions shown. A model of the boxcar is 1.25 inches wide. Find the length of the model to nearest inch.

sashaice [31]

X - the length of the model:
36.25 : 9 = x : 1.25
9 x = 36.25 · 1.25
9 x = 45.3125
x = 5.03 ≈ 5 inches.

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2 years ago

Expand and simplify this <br>can you help <br>(2x²−3x+4) ( x²+5x−7)

Burka [1]

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2 years ago

Keith is a gardener and he can plant 40 bushes in 8 hours. How many bushes can he plant in 2 hours?

inn [45]

Answer:

Keith can plant 10 bushes in 2 hours

Step-by-step explanation:

40 divided by 8 is 5 and 5 times 2 is 10.

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2 years ago

Find the largest interval which includes x = 0 for which the given initial-value problem has a unique solution. (Enter your answ

Ivan

Answer:

$(-\infty,3)$

Step-by-step explanation:

We are given that

$(x-3)y''+4y=x$

$y''+\frac{4}{x-3}y=\frac{x}{x-3}$

y(0)=0

y'(0)=1

By comparing with

$y''+p(x)y'+q(x)y=g(x)$

We get

$p(x)=\frac{4}{x-3}$

$g(x)=\frac{x}{x-3}$

q(x)=0

p(x),q(x) and g(x) are continuous for all real values of x except 3.

Interval on which p(x),q(x) and g(x) are continuous

$(-\infty,3)$ and (3, $\infty)$

By unique existence theorem

Largest interval which contains 0= $(-\infty,3)$

Hence, the larges interval on which includes x=0 for which given initial value problem has unique solution= $(-\infty,3)$

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2 years ago

May I please get help with all the questions

bogdanovich [222]

Answer:

1. g(3) = 1

2. (f + g)(2) = f(2) + g(2) = 2 + 3 = 5

3. f(g(4)) = 2

4. g(f(4)) = 1

5. f(f(4)) = 2

6. g(g(2)) = 1

7. base on the chart, the value 3 of g(x) can be gain only for x = 0

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2 years ago