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3 years ago

What is the y-intercept of an equation

Mathematics

2 answers:

Alona [7]3 years ago

8 0

Answer:

The y interpit means the y-axis. you should've known this in 5th grade.

Step-by-step explanation:

krek1111 [17]3 years ago

4 0

Answer:

The point on a graph where a line crosses the Y-axis (The vertical line)

Step-by-step explanation:

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If x and x+ 10 are a pair of adjacent angle find them

ikadub [295]

Answer:

85° and 95°

Step-by-step explanation:

Given that , x and x + 10 are a pair of angles .

If they will be pair of angles on the same line , then their sum will be 180° .

=> x + x + 10° = 180°

=> 2x = 180° -10°

=> 2x = 170°

=> x = 170°/2

=> x = 85° .

<h3>Hence the two angles are 85° and 95° .</h3>

5 0

3 years ago

Which graph represents the function y = 4?

expeople1 [14]

Answer:

answer is ABCD

Step-by-step explanation:

I took the quiz

6 0

3 years ago

A ball is launched straight up in the air from a height of 6 feet. Its velocity (feet/second) t seconds after launch is given by

german

Step-by-step explanation:

A ball is launched straight up in the air from a height of 6 feet. The velocity as a function of time t is given by :

f(t) = -32 t+285

Height of the ball is :

$h(t)=\int\limits{f(t){\cdot} dt}\\\\h(t)=\int\limits{(-32t+285){\cdot} dt}\\\\h(t)=-16t^2+285t+C$

C is constant. Here the ball is launched from a height of 6 feet. So,

$h(t)=-16t^2+285t+6$

At t = 2 s, $h(t)=-16(2)^2+285(2)+6=512\ m$

At t = 9 s, $h(t)=-16(9)^2+285(9)+6=1275\ m$

Between 2 s and 9 s, the ball's height changed is : 1275 - 512 = 763 m.

6 0

3 years ago

Plz help me find sides M and N round to the nearest tenth

Sergio [31]

Answer:

Step-by-step explanation:

gradpoint

6 0

3 years ago

For the region bounded by y=2x, the x-axis, and x=1, determine which of the following is greater: the volume of the solid ge

telo118 [61]

Answer:

The correct answer B) The volumes are equal.

Step-by-step explanation:

The area of a disk of revolution at any x about the x- axis is πy² where y=2x. If we integrate this area on the given range of values of x from x=0 to x=1 , we will get the volume of revolution about the x-axis, which here equals,

$\int\limits^1_0 {(pi)y^{2} } \, dx$

which when evaluated gives 4pi/3.

Now we have to calculate the volume of revolution about the y-axis. For that we have to first see by drawing the diagram that the area of the CD like disk centered about the y-axis for any y, as we rotate the triangular area given in the question would be pi - pi*x². if we integrate this area over the range of value of y that is from y=0 to y=2 , we will obtain the volume of revolution about the y-axis, which is given by,

$\int\limits^2_0 {pi - pix^{2} } \, dy = \int\limits^2_0 {1 - y^{2}/4 } \, dy$

If we just evaluate the integral as usual we will get 4pi/3 again(In the second step i have just replaced x with y/2 as given by the equation of the line), which is the same answer we got for the volume of revolution about the x-axis. Which means that the answer B) is correct.

7 0

3 years ago