Subtract thats how you get it
When we are given 3 sides, we try to solve the angles first by using the
law of cosines
cos (A) = [b^2 + c^2 - a^2] / (2 * b * c)
cos (A) = [43^2 + 17^2 -27^2] / (2 * 43 * 17)
cos (A) = [1,849 + 289 -729] /
<span>
<span>
<span>
1,462
</span></span></span>cos (A) = 1,409 / 1,462
cos (A) =
<span>
<span>
<span>
0.96374829001368
Angle A = 15.475
Now that we have one angle, we next can use the
Law of Sines
sin(B) / side b = sin(A) / side a
sin(B) = sin(A) * sideb / sidea
</span></span></span><span>sin(B) = sin(15.475) * 43 / 27
</span><span>sin(B) = 0.26682 * 43 / 27
sin (B) = </span><span>0.424935555555</span>
Angle B = 25.147 Degrees
Remember the arc sine (<span>0.424935555555) also equals </span>
<span>
<span>
<span>
154.85
</span></span></span>Finally, calculating the third angle is quite easy
Angle C = 180 - Angle (A) - Angle(B)
Angle C = 180 - 15.475 - 154.85
Angle C = 9.675
Source:
http://www.1728.org/trigtut2.htm
Answer:
Rhian did better in the Math test.
Step-by-step explanation:
Given: Rhian scored 
out of 
in a Math test. In the English test she scored 
out of 
.
To find: In which test did she do better?
Solution:
We have,
Rhian scored out of in a Math test.
Rhian scored out of in an English test.
So, first we need to find the percentage of the marks scored.
Percentage in the Math test 
.
Percentage in the English test 
.
Clearly, the percentage in the Math test is greater than the percentage in the English test.
So, Rhian did better in the Math test.
(50,45)(125,37.50)
slope(m) = (37.50 - 45) / (125 - 50) = -7.5/75 = -0.1
y = mx + b
slope(m) = -0.1
(50,45)...x = 50 and y = 45
now we sub and find b, the y int
45 = -0.1(50) + b
45 = - 5 + b
45 + 5 = b
50 = b
so ur equation is : y = -0.1x + 50
so it the staff sells 150 yearbooks...
y = -0.1x + 50
y = -0.1(150) + 50
y = -15 + 50
y = 35 <== price per yearbook
