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Andrei [34K]
2 years ago
5

It’s simple I swear!!! what is the square root of 25 times the square root of 9

Mathematics
2 answers:
goldenfox [79]2 years ago
6 0

Answer:

15

Step-by-step explanation:

1st multiply the numbers: 25 × 9 = 225

2nd factor the number: 225 = √15^2

3rd apply radical rule: √15^2 = 15

Hope I helped :)

Lyrx [107]2 years ago
6 0

Answer:25 square root of 9

=25^9

Step-by-step explanation: if its a graph go to wolfram to see it because i cant draw it .

I hope I helps you.

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3 years ago
X-y=6<br> 2x-3z=16<br> 2y+z=4<br><br> Solve the systems of equations.
Neko [114]

Answer:

Given System of equation:

x-y =6                                  .....,[1]

2x-3z = 16                           ......[2]  

2y+z = 4                              .......[3]

Rewrite the equation [1] as

y = x - 6                                .......[4]

Substitute the value of [4] in [3], we get

2(x-6)+z = 4

Using distributive property on LHS ( i.e,  a \cdot (b+c) =a \cdot b+ b \cdot c )

then, we have

2x - 12 +z =4

Add 12 to both sides of an equation:

2x-12+z+12=4+12

Simplify:

2x +z = 16                         .......[5]

On substituting equation [2] in [5] we get;

2x+z=2x -3z

or

z = -3z

Add 3z both sides of an equation:

z+3z = -3z+3z

4z = 0

Simplify:

z = 0

Substitute the value of z = 0 in [2] to solve for x;

2x-3(0) = 16

or

2x = 16

Divide by 2 both sides of an equation:

\frac{2x}{2} =\frac{16}{2}

Simplify:

x= 8

Substitute the value of x =8 in equation [4] to solve for y;

y = 8-6 = 2

or

y = 2

Therefore, the solution for the given system of equation is;  x = 8 , y = 2 and z =0

5 0
3 years ago
Solve for the equation 4a-8=28
hoa [83]
4a-8=28
add 8 to both sides to start to isolate the variable (a)
-8+8 cancels each other out
28+8=36
4a=36
to completely isolate the variable divide both sides by 4
4a÷4=a
36÷4=9
a=9
6 0
3 years ago
Please help my assignment
m_a_m_a [10]
There is no solution since ln(0) is undefined
3 0
2 years ago
Find: (6m5 3 â€"" m3 â€"" 4m) â€"" (â€""m5 2m3 â€"" 4m 6) Write subtraction of a polynomial expression as addition of the additi
aliina [53]

The subtraction in the standard form of the polynomial is \rm 7m^5-3m^2-3.

Given that

Expression; \rm (6m^5 + 3 - m^3 -4m) -(-m^5 + 2m^3 - 4m + 6).

We have to determine

The subtraction of a polynomial.

According to the question

Expression; \rm (6m^5 + 3 - m^3 -4m) -(-m^5 + 2m^3 - 4m + 6).

To find the subtraction of the polynomial follow all the steps given below.

  • Step1; Write the expression as an additive inverse.

                   \rm (6m^5 + 3 - m^3 -4m) -(-m^5 + 2m^3 - 4m + 6)\\\\\rm (6m^5 + 3 - m^3 -4m) +(m^5 -2m^3 +4m - 6)

  • Step2; Rewrite terms that are subtracted as the addition of the opposite.

        \rm (6m^5 + 3 - m^3 -4m) +(m^5 -2m^3 +4m - 6)\\\\6m^5 + 3 + (-m^3) + (-4m) + m^5 + (2m^3) + 4m + (-6)

  • Step3; Group-like terms.

                   \rm 6m^5 + 3 + (-m^3) + (-4m) + m^5 + (2m^3) + 4m + (-6)\\\\(6m^5 + m^5) + [3 + (-6)] + [(-m^3) + (-2m^3)] + [(-4m) + 4m]\\\\

  • Step4; the resulting polynomial in standard form is,

                    \rm (6m^5 + m^5) + [3 + (-6)] + [(-m^3) + (-2m^3)] + [(-4m) + 4m]\\\\ 7m^5-3m^2-3

                   

Hence, the subtraction in the standard form of the polynomial is \rm 7m^5-3m^2-3.

To know more about Polynomial click the link given below.

brainly.com/question/26078031

                   

3 0
2 years ago
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