Answer:
Option A - Permutation; number of ways = 210
Step-by-step explanation:
Given : At a competition with 7 runners, medals are awarded for first, second, and third places. Each of the 3 medals is different.
To find : How many ways are there to award the medals?
Solution :
There are 7 runners but medals are three.
The first runner up got first medal as one is locked.
The second runner up got second medal as second is locked.
The third runner up got the third medal.
So, There is a permutation.
Number of ways to award the medals is 
We know, 
Substitute the values,
Therefore, Option A is correct.
Permutation; number of ways = 210
First you get "y" by itself. To do so you divide 2 on both sides.
y = 3/2x + 5
To write an equation of a line that is PARALLEL to this equation, the slopes have to be the SAME. So the slope is 3/2.
You then use the equation:
y = mx + b
SInce you know "m" you plug it in.
y = 3/2x + b
Now you need to find b. To do so you plug in the point (2, -5) into this equation.
-5 = 3/2(2) + b
-5 = 3 + b
-8 = b
Finally you plug in b and you get your new equation.
y = 3/2x - 8
Answer:
For this case we have the following equation:
Ax - By = C
From here, we must clear the value of x.
Adding By on both sides:
Ax = By + C
Then, dividing both sides by A we have:
x =By +C/A
Answer:
x = By+C/A
x equals the quantity B times and plus C all over A
Answer:
84 is the highest possible course average
Step-by-step explanation:
Total number of examinations = 5
Average = sum of scores in each examination/total number of examinations
Let the score for the last examination be x.
Average = (66+78+94+83+x)/5 = y
5y = 321+x
x = 5y -321
If y = 6, x = 5×6 -321 =-291.the student cannot score -291
If y = 80, x = 5×80 -321 =79.he can still score higher
If If y = 84, x = 5×84 -321 =99.This would be the highest possible course average after the last examination.
If y= 100
The average cannot be 100 as student cannot score 179(maximum score is 100)
