The second one is the answer.
Hello!
Vertical asymptotes are determined by setting the denominator of a rational function to zero and then by solving for x.
Horizontal asymptotes are determined by:
1. If the degree of the numerator < degree of denominator, then the line, y = 0 is the horizontal asymptote.
2. If the degree of the numerator = degree of denominator, then y = leading coefficient of numerator / leading coefficient of denominator is the horizontal asymptote.
3. If degree of numerator > degree of denominator, then there is an oblique asymptote, but no horizontal asymptote.
To find the vertical asymptote:
2x² - 10 = 0
2(x² - 5) = 0
(x - √5)(x + √5) = 0
x = √5 and x = -√5
Graphing the equation, we realize that x = -√5 is not a vertical asymptote, so therefore, the only vertical asymptote is x = √5.
To find the horizontal asymptote:
If the degree of the numerator < degree of denominator, then the line, y = 0 is the horizontal asymptote.
Therefore, the horizontal asymptote of this function is y = 0.
Short answer: Vertical asymptote: x = √5 and horizontal asymptote: y = 0
Answer: The function that models the distance they drive is
f(x) = 50x + 20 where x is the time in hours
reasonable domain: 0 ≤ x ≤ 3
Step-by-step explanation:
examples:
95 = 50(1.5) + 20 After driving another hour and a half, they will have driven a total of 95 miles.
120 = 50(2) + 20 This means that after 2 more hours they will reach their destination.
There is a little ambiguity in the question. The function could be written as if they are starting out. f(x) = 50t
20 = 50(.4) At 50 mph it took .4 hours to go 20 miles.
120 = 5(2.4) The whole trip took 2.4 hours.