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3 years ago

How do I rewrite a quadratic into graphing form

Mathematics

1 answer:

Juli2301 [7.4K]3 years ago

3 0

Step-by-step explanation:

Standard form of a quadratic is f(x) = ax² + bx + c.

To convert to vertex form, the simplest method is to find the x-coordinate of the vertex using h = -b/(2a).

Then, plug back into the equation to find the y-coordinate of the vertex. k = f(h).

Finally, the leading coefficient is the same as the standard form, a.

f(x) = a(x − h)² + k

Another method is to complete the square.

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Which of the following expressions is equal to 1 divided by 16

Mama L [17]

Answer:

Step-by-step explanation:

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3 years ago

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The vertices of ∆ABC are A(-2, 2), B(6, 2), and C(0, 8). The perimeter of ∆ABC is units is? What is the area?

11111nata11111 [884]

we have

$A(-2, 2),B(6, 2),C(0, 8)$

see the attached figure to better understand the problem

we know that

The perimeter of the triangle is equal to

$P=AB+BC+AC$

and

the area of the triangle is equal to

$A=\frac{1}{2}*base *heigth$

in this problem

$base=AB\\heigth=DC$

we know that

The distance between two points is equal to

$d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}$

Step $1$

Find the distance AB

$A(-2, 2),B(6, 2)$

Substitute the values in the formula

$d=\sqrt{(2-2)^{2}+(6+2)^{2}}$

$d=\sqrt{(0)^{2}+(8)^{2}}$

$dAB=8\ units$

Step $2$

Find the distance BC

$B(6, 2),C(0, 8)$

Substitute the values in the formula

$d=\sqrt{(8-2)^{2}+(0-6)^{2}}$

$d=\sqrt{(6)^{2}+(-6)^{2}}$

$dBC=6\sqrt{2}\ units$

Step $3$

Find the distance AC

$A(-2, 2),C(0, 8)$

Substitute the values in the formula

$d=\sqrt{(8-2)^{2}+(0+2)^{2}}$

$d=\sqrt{(6)^{2}+(2)^{2}}$

$dAC=2\sqrt{10}\ units$

Step $4$

Find the distance DC

$D(0, 2),C(0, 8)$

Substitute the values in the formula

$d=\sqrt{(8-2)^{2}+(0-0)^{2}}$

$d=\sqrt{(6)^{2}+(0)^{2}}$

$dDC=6\ units$

Step $5$

Find the perimeter of the triangle

$P=AB+BC+AC$

substitute the values

$P=8\ units+6\sqrt{2}\ units+2\sqrt{10}\ units$

$P=22.81\ units$

therefore

The perimeter of the triangle is equal to $22.81\ units$

Step $6$

Find the area of the triangle

$A=\frac{1}{2}*base *heigth$

in this problem

$base=AB=8\ units\\heigth=DC=6\ units$

substitute the values

$A=\frac{1}{2}*8*6$

$A=24\ units^{2}$

therefore

the area of the triangle is $24\ units^{2}$

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3 years ago

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Simplify the expression fraction with numerator of the square root of negative one and denominator of the quantity three plus ei

Ainat [17]

The right answer for the question that is being asked and shown above is that: "fraction with numerator negative 3 minus i and denominator 10." This is the simplified expression fraction with numerator of the square root of negative one and denominator of the quantity three plus eight times i minus the quantity two plus five times i.

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6 1/2 - 7/8 : 5 11/16

Komok [63]

Answer:

Step-by-step explanation:

brainly.com/question/6752935

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3 years ago

Lee has $1.75 in dimes and nickels. The number of nickels is 11 more than the number of dimes. How many of each coin does he hav

Schach [20]

Answer:

Lee has 19 nickels and 8 dimes

Step-by-step explanation:

hello, I think I can help you with this

Step 1

Let

value of a nickel=$0.05

value of a dime=$0.10

number of nickels=N

number of nickels=D

According to the question data Lee has $1.75 in dimes and nickels.

0.05N+0.1D=1.75,equation(1)

also, the number of nickels is 11 more than the number of dimes.mathematical speaking

N=11+D,equation(2)

Step 2

replace N from equation (2) into equation (1)

0.05N+0.1D=1.75

0.05(11+D)+0.1D=1.75

Now, solve for D

0.55+0.05D+0.1D=1.75

0.15D=1.75-0.55

D=1.2/0.15

D=8

Step 3

replace the value of D into equation(2) to obtain N

N=11+8

N=19

Hence, Lee has 19 nickels and 8 dimes

Have a great day.

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3 years ago