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2 years ago

2 complementary angles are in the ratio 3:6. Find the angles

Mathematics

1 answer:

pentagon [3]2 years ago

3 0

Answer:

The angles are 60°, and 30°

Step-by-step explanation:

Complementary angles add up to 90°

3 = 6 = 9

90/9 = 10

10 * 3 = 30

10 * 6 = 60

-Chetan K

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A recent college graduate is planning to take the first three actuarial examinations in the coming summer. She will take the fir

erica [24]

Answer:

(a) 0.7

(b) $\frac 13$

Step-by-step explanation:

Let $E_1, E_2,$ and $E_3$ be the events of passing the 1st, 2nd, and 3rd exam individually.

Given that $P(E_1)=0.9\;\cdots(i)$

where $P(E_1)$ denotes the probability of passing the 1st exam.

Condition for passing the second exam is, at first, the candidate must have to pass the 1st exam.

So, $P\left(\frac{E_2}{E_1}\right)=0.8\;\cdots(ii)$

where $P(E_2/E_1)$ denotes the probability of passing the 2nd exam when she already passed the 1st exam (given, 0.8).

Similarly, as the conditional probability of passing the 3rd exam is 0.7, and the condition for this is, at first, she must have to pass the 1st and 2nd exam. i.e,

$P\left(\frac{E_2}{P(E_2/E_1)}\right)=0.7\;\cdots(iii)$

(a) For passing all the exams, the condition is, at first, she has to pass the 1st and 2nd exam, then she has to pass the 3rd exam too. The probability for this conditional has been given as 0.7.

So, the probability that she passes all three exams is 0.7.

(b) Given that she didn't pass all three exams that means she either failed in 1st exam or she passed the 1st and failed in 2nd exam or she passed both 1st and 2nd but failed in the 3rd exam.

Let F be the event that she didn't pass all three exams. So,

$P(F)=(1-P(E_1))+\left(1-\frac{P(E_2)}{P(E_1)}\right)+\left(1-\frac{P(E_2)}{P(E_2/E_1)}}\right)$

$\Rightarrow P(F)=(1-0.9)+(1-0.8)+(1-0.7)=0.6$

Lef $F_2$ be the event that she failed the 2nd exam, so

$P(F_2)=1-\frac{P(E_2)}{P(E_1)}$

$\Rightarrow P(F_2)=1-0.8=0.2$

So, the conditional probability that she failed the 2nd exam is

$P\left(\frac{F_2}{F}\right)=\frac{P(F_2)}{P(F)}$

$\Rightarrow P\left(\frc{F_2}{F}\right)=\frac{0.2}{0.6}=\frac{1}{3}=0.33$

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2 years ago

select true or false to tell whether the following conditional pq is true or false. use the truth table if needed. if dogs have

r-ruslan [8.4K]

Answer:

Step-by-step explanat

that's true dog have 4 and cat so

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2 years ago

Write each ratio statement as a fraction and reduce the two lowest terms 14:42

LuckyWell [14K]

<span>14:42 = 14/42 = 1/3
</span>This ones right sorry answered wrong question lol

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3 years ago

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your mother gave you 14.28 with which to buy a present. this covered 3/4 of the cost. how much did the present cost?

saul85 [17]

$19.04. If your mom gave you $14.28, and it only covered 3/4 of the cost, you have to first find 3/4 as a percentage, and then put it into a decimal. It would be 0.75. So then you have to divide 14.28÷0.75. It turns out to be $19.04.

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2 years ago

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Tanya [424]

Domain: All real numbers (-infinity, infinity)

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1 year ago

2 complementary angles are in the ratio 3:6. Find the angles​

2 complementary angles are in the ratio 3:6. Find the angles