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Vlada [557]
3 years ago
10

an equation for the line perpendicular to the line 4x + 8y = 7 having the same y -intercept as −3x + 5y = −2

Mathematics
1 answer:
castortr0y [4]3 years ago
8 0
<span>4x + 8y = 7
8y = -4x + 7
y = -1/2x + 7/8 this equation has slope = -1/2

</span><span>line perpendicular to the line 4x + 8y = 7, so the slope = 2 

</span><span>same y -intercept as −3x + 5y = −2 
</span><span> y intercept means x = 0
</span> 5y = −2 
 y = -2/5
so
b = -2/5
 
answer:
 equation: 

y = 2x - 2/5

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Describe how the graph of y=x^2 can be transformed to the graph of the given equation y=x^2-20
FinnZ [79.3K]

We can transform this function by adding a constant to the original equation y=x^2. A new transformed function g(x) is given by g(x)=f(x)+c (where f(x)=y)

c>0 moves it up

c<0 moves it down

So: y=x^2+c

y=x^2-20

The new graph will be 20 units down the original.

4 0
3 years ago
Read 2 more answers
9. If the area of a rectangle measures 20 square inches, the side lengths
DochEvi [55]

Answer:

True

Step-by-step explanation:

The given statement is true.

Area of a rectangle is length times width.

A rectangle with the side length of 4 and 5 inches would have an area of 20 square inches.

A=l*w\\\\A=4*5\\\\A=20

Hope this helps.

3 0
3 years ago
A company is in the business of finding addresses of long-lost friends. The company claims to have a 70% success rate. Suppose t
Galina-37 [17]

Answer:

a) Figure attached

b) E(X) =\mu= np = 9*0.7=6.3

Sd(X) =\sigma= \sqrt{np(1-p)}= \sqrt{9*0.7*(1-0.7)}=1.375

c) For the case n= 6

P(X \leq 2) = 0.9891

For the case n= 5

P(X \leq 2) = 0.9692

So then we need at least  n=5 or n=6 to satisfy the condition required.

Step-by-step explanation:

Previous concepts

The binomial distribution is a "DISCRETE probability distribution that summarizes the probability that a value will take one of two independent values under a given set of parameters. The assumptions for the binomial distribution are that there is only one outcome for each trial, each trial has the same probability of success, and each trial is mutually exclusive, or independent of each other".

Solution to the problem

Let X the random variable of interest, on this case we now that:

X \sim Binom(n=9, p=0.7)

The probability mass function for the Binomial distribution is given as:

P(X)=(nCx)(p)^x (1-p)^{n-x}

Where (nCx) means combinatory and it's given by this formula:

nCx=\frac{n!}{(n-x)! x!}

Part a

For this case we can use the following R code:

> x <- seq(0,9,by = 1)

> y <- dbinom(x,9,0.7)

> plot(x,y,main="Histogram",type = "h")

And we can see on the figure attached the solution.

We see that the higher probabilities are from 4 to 9

Part b

The expected value is given by:

E(X) =\mu= np = 9*0.7=6.3

The variance is given by:

Var (X) =\sigma^2= np(1-p) = 9*0.7*(1-0.7)= 1.89

And the standard deviation is:

Sd(X) =\sigma= \sqrt{np(1-p)}= \sqrt{9*0.7*(1-0.7)}=1.375

Part c

First we can find the probability that at least two addresses will be found in the list of 9 that we have like this:

P(X \geq 2)

We can use the complement rule and we have:

P(X \geq 2) = 1-P(X

We find the indicidual probabilities:

P(X=0)=(9C0)(0.7)^0 (1-0.7)^{9-0}=0.00001968

P(X=1)=(9C1)(0.7)^1 (1-0.7)^{9-1}=0.000413

P(X \geq 2) = 1-[0.00001968+0.000413]=0.9996

If we use the case of n=8 and we find P(X\leq 2), we got:

P(X \leq 2) = 0.9987

For the case n= 7

P(X \leq 2) = 0.9962

For the case n= 6

P(X \leq 2) = 0.9891

For the case n= 5

P(X \leq 2) = 0.9692

So then we need at least  n=5 or n=6 to satisfy the condition required.

5 0
3 years ago
Please solve for the triangle! Thank you
Katena32 [7]
78-32=56
56=2x
x=28

X is equivalent to 28
3 0
4 years ago
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