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vovangra [49]
3 years ago
8

Describe how the graph of y=x^2 can be transformed to the graph of the given equation y=x^2-20

Mathematics
2 answers:
brilliants [131]3 years ago
8 0

Answer: The graph of the equation y=x^2 can be transformed to the graph of the equation y=x^2-20 by shifting y=x^2  20 units downward.

Step-by-step explanation:

Some transformations for a function f(x):

If f(x)+k, the function is shifted "k" units upward.

If f(x)-k, the function is shifted "k" units downward.

Knowing these transformations and given these equations:

y=x^2 and y=x^2-20  

We can concluse that the graph of the equation y=x^2 can be transformed to the graph of the equation y=x^2-20 by shifting y=x^2  20 units downward.

FinnZ [79.3K]3 years ago
4 0

We can transform this function by adding a constant to the original equation y=x^2. A new transformed function g(x) is given by g(x)=f(x)+c (where f(x)=y)

c>0 moves it up

c<0 moves it down

So: y=x^2+c

y=x^2-20

The new graph will be 20 units down the original.

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3 0
3 years ago
. Consumer Awareness In 1986, the average cost of a new midsize four-door sedan was $9000. In 1991, the average cost was $12,000
eduard

<u>Answer-</u>

\boxed{\boxed{y=9000(1.0592)^x}}

<em>And cost of a car in the year 2000 will be </em><em>$20134.18</em>

<u>Solution-</u>

Let's assume,

x = number of years after 1986

y = average cost of sedan in dollar

The exponential model that will model the scenario will be in the form of,

y=ab^x

where a and b are constants

As given that, in 1986 average cost of sedan was $9000 and in 1991 average cost of sedan was $12000

So, the points (0, 9000) and (5, 12000) will satisfy or lie on the exponential curve.

Putting (0, 9000) in the equation,

\Rightarrow 9000=ab^0

\Rightarrow a\times 1=9000

\Rightarrow a=9000

Now, the equation becomes y=9000b^x

Putting (5, 12000) in this equation,

\Rightarrow 12000=9000b^5

\Rightarrow b^5=\dfrac{12000}{9000}

\Rightarrow b=\sqrt[5]{\dfrac{4}{3}}

\Rightarrow b=1.0592

Putting the values,

y=9000(1.0592)^x

As we have to calculate the cost of sedan in 2000, so putting x=14(as 2000-1986=14),

y=9000(1.0592)^{14}=20134.18

Therefore, cost of a car in the year 2000 will be $20134.18

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3 years ago
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<span>identity property of addition</span>
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