Looking at this problem in terms of geometry makes it easier than trying to think of it algebraically.
If you want the largest possible x+y, it's equivalent to finding a rectangle with width x and length y that has the largest perimeter.
If you want the smallest possible x+y, it's equivalent to finding the rectangle with the smallest perimeter.
However, the area x*y must be constant and = 100.
We know that a square has the smallest perimeter to area ratio. This means that the smallest perimeter rectangle with area 100 is a square with side length 10. For this square, x+y = 20.
We also know that the further the rectangle stretches, the larger its perimeter to area ratio becomes. This means that a rectangle with side lengths 100 and 1 with an area of 100 has the largest perimeter. For this rectangle, x+y = 101.
So, the difference between the max and min values of x+y = 101 - 20 = 81.
0, because anything times 0 equals 0.
Answer: 10+.6
Step-by-step explanation: be more specific
The algebraic expressions can be written as
The given expression is,
Answer:
Step-by-step explanation:
yes congruent, by AAS
the angles are stating , w/ the little red lines that they are the same.. so we know two angles of the triangles are the same, and we also know that one side touching is the same. so yes.. AAS.
