The solution for the system of linear equations 2x- y = 3 and y - x = 1 are x = 4 and y = 5
<h3>What are linear equations?</h3>
Linear equations are equations that have constant average rates of change, slope or gradient
<h3>How to determine the solution to the system?</h3>
A system of linear equations is a collection of at least two linear equations.
In this case, the system of equations is given as
2x- y = 3
y - x = 1
Make y the subject in the second equation, by adding x to both sides of the equation
y - x + x = x + 1
This gives
y = x + 1
Substitute y = x + 1 in 2x- y = 3
2x- x - 1 = 3
Evaluate the like terms
x = 4
Substitute x = 4 in y = x + 1
y = 4 + 1
Evaluate
y = 5
Hence, the solution for the system of linear equations 2x- y = 3 and y - x = 1 are x = 4 and y = 5
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Here is all I got for you. From the starting expression to the simplest one.
t^2 + 4tv + 4^2 =
t^2 + 4tv + 16 =
t(t + 4v) + 16
x equals negative 8 and negative 4
Answer:
0.15
Step-by-step explanation:
Fp: frequency that the pitcher will throw exactly 4 pitches to a batter=15
Fa: frequency that the pitcher will throw any pitches to a batter=15+20+40+15+10=100
P=Fp/Fa=15/100=0.15
