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Nataly [62]
4 years ago
6

A terrarium is built in the shape of a triangular prism. The prism is 10 inches in height and contains 450 cubic inches of space

. A triangular prism is shown. The prism is 10 inches in height and contains 450 cubic inches of space. What is the area of the base shape of the prism?
Mathematics
1 answer:
Olenka [21]4 years ago
8 0

Answer:

The area of the prism’s base is 45 square inches

Step-by-step explanation:

Mathematically, to calculate the volume or the amount of space in the triangular prism, we have to multiply the area of the base by the height of the prism.

Volume of prism = height of prism * base area of prism

From the question, we identify the height as 10 inches with the volume being 450 inches^3

Plugging these values we have;

Area of prism base = volume of prism/ height of prism = 450/10 = 45 inches^2

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(7.02) classify each sequence as arithmetic, geometric, or neither.
Digiron [165]

Answer:

geometric

arithmetic

arithmetic

Step-by-step explanation:

1.

4/9,4/3,4,12,36

Multiply each term by 3 to get the next term. There is a common ratio between terms, so it geometric.

2.

0,1,2,3,4,5,6

Add 1 to each term to get the next term. Since there is a common difference between terms, it is an arithmetic sequence.

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3 years ago
Q20-23 with steps pls
just olya [345]

20: Let x be the amount of money. If this amount is shared between 8 people, each person will get x/8 dollars. But there actually are 6 people, so everyone is getting x/6 dollars. We know that this difference results in 30 dollars more, so we have

\dfrac{x}{6}=\dfrac{x}{8}+30 \iff \dfrac{x}{6}-\dfrac{x}{8}=30

Rearrange the left hand side as

\dfrac{4x-3x}{24}=30

And multiply both sides by 24 to get

x=720

21: Let M and J be the number of marbles owned by Mike and Judy, respectively. At the beginning, we have

M=3J+11

If they both get 9 more marbles, Mike will have M+9 marbles, and Judy will have J+9 marbles. So, we have

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75-J=3J+11 \iff 4J=64 \iff J=16

And we deduce

M=16\cdot 3 + 11=59

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M-J=59-16=43

22: Let x,y,z be the number of $10, $20 and $50 coupon, respectively. We're given:

\begin{cases}x=2y+3\\z=\frac{1}{2}y\\x+y+z=38\end{cases}&#10;We can write the third equation by substituting the expressions for x and z:&#10;[tex]x+y+z=(2y+3)+y+\left(\dfrac{1}{2}y\right)=38

Rearrange as follows:

(2y+3)+y+\left(\dfrac{1}{2}y\right)=38 \iff \dfrac{7}{2}y=35 \iff 7y=70 \iff y=10

And now we can deduce the number of the other coupons:

x=2\cdot 10+3=23,\quad z=\dfrac{1}{2}\cdot 10=5

So, the total value is

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a_1=4\cdot 1+3=7,\quad a_2=4\cdot 2+3=11,\quad a_3=4\cdot 3+3=15

b) We have

a_r = 4r+3=71 \iff 4r=68 \iff r=\dfrac{68}{4}=17

c) 105 is a term of the sequence if and only if there exists an integer k such that

a_k=4k+3=105 \iff 4k = 102 \iff k=\dfrac{102}{4}=25.5

So, 105 is not a term of the sequence.

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weqwewe [10]
Rewrite the parabola in standard form and use this formula to find the vertex (h,k).
= (2,-1)

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3 years ago
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