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3 years ago

What is the vertex of the parabola given by = -(x-2)^2-1?

Mathematics

1 answer:

weqwewe [10]3 years ago

3 0

Rewrite the parabola in standard form and use this formula to find the vertex (h,k).
= (2,-1)

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A ratio of angel fish at a store is 5:4. the ratio of angel fish to goldfish is 4:3 . There are 60 clown fish at the pet store

dexar [7]

Answer:

an i oop

Step-by-step explanation:

6 0

3 years ago

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PLEASE HELP ASAP. Don’t send a link just put the answer. I’ll give brainpower to whoever answers!!!!!

givi [52]

Answer:

d/c = 8

Step-by-step explanation:

f(x) = 5.4321×2^×

f(4) = 5.4321×2^4 = d

f(1) = 5.4321×2^1 = c

d/c = (5.4321×2^4)/(5.4321×2^1) = 2^3 = 8

6 0

2 years ago

Help please with 9 and 10 please !

Lana71 [14]

Answer:

9. The scale factor is 1.5.

10. scale factor = 0.75

the missing side is 9m

Step-by-step explanation:

9. 3/2 = 1.5

9/6 = 1.5

6/4 = 1.5

10. 12/16 = 0.75

12*0.75 = 9

3 0

2 years ago

Read 2 more answers

Please Help ASAP

Orlov [11]

The C(x) equation is a parabola with a squared "x" and a positive leading term coefficient, meaning, is a vertical parabola and it opens upwards

the lowest point, or lowest cost value, it reaches, is the U-turn point, or vertex

$\bf \textit{ vertex of a vertical parabola, using coefficients}\\\\
\begin{array}{llccll}
y = &{{ 1}}x^2&{{ -320}}x&{{ +40052}}\\
&\uparrow &\uparrow &\uparrow \\
&a&b&c
\end{array}\qquad 
\left(-\cfrac{{{ b}}}{2{{ a}}}\quad ,\quad {{ c}}-\cfrac{{{ b}}^2}{4{{ a}}}\right)$

so, the lowest cost is at $\bf {{ c}}-\cfrac{{{ b}}^2}{4{{ a}}}$

8 0

3 years ago

-6n5x^3÷18nx^7<br>12m^8y^6÷-9my^4

umka2103 [35]

Answer:

(-n^4 - 4 m^7 x^4 y^2)/(3 x^4)

Step-by-step explanation:

Simplify the following:

(-6 n^5 x^3)/(18 n x^7) + (12 m^8 y^6)/(-9 m y^4)

The gcd of -6 and 18 is 6, so (-6 n^5 x^3)/(18 n x^7) = ((6 (-1)) n^5 x^3)/((6×3) n x^7) = 6/6×(-n^5 x^3)/(3 n x^7) = (-n^5 x^3)/(3 n x^7):

(-1 n^5 x^3)/(3 n x^7) + (12 m^8 y^6)/(-9 m y^4)

Combine powers. (-n^5 x^3)/(3 n x^7) = (n^(5 - 1) x^(3 - 7) (-1))/3:

-(n^(5 - 1) x^(3 - 7))/3 + (12 m^8 y^6)/(-9 m y^4)

5 - 1 = 4:

-(n^4 x^(3 - 7))/3 + (12 m^8 y^6)/(-9 m y^4)

3 - 7 = -4:

-(n^4 x^(-4))/3 + (12 m^8 y^6)/(-9 m y^4)

The gcd of 12 and -9 is 3, so (12 m^8 y^6)/(-9 m y^4) = ((3×4) m^8 y^6)/((3 (-3)) m y^4) = 3/3×(4 m^8 y^6)/(-3 m y^4) = (4 m^8 y^6)/(-3 m y^4):

(4 m^8 y^6)/(-3 m y^4) - (n^4)/(3 x^4)

Combine powers. (4 m^8 y^6)/(-3 m y^4) = (4 m^(8 - 1) y^(6 - 4))/(3 (-1)):

-(n^4)/(3 x^4) + (4 m^(8 - 1) y^(6 - 4))/(-3)

8 - 1 = 7:

-(n^4)/(3 x^4) + (4 m^7 y^(6 - 4))/(-3)

6 - 4 = 2:

-(n^4)/(3 x^4) + (4 m^7 y^2)/(-3)

Multiply numerator and denominator of (4 m^7 y^2)/(-3) by -1:

-4/3 m^7 y^2 - (n^4)/(3 x^4)

Put each term in -(n^4)/(x^4×3) - (4 m^7 y^2)/3 over the common denominator 3 x^4: -(n^4)/(x^4×3) - (4 m^7 y^2)/3 = (-n^4)/(3 x^4) - (4 m^7 x^4 y^2)/(3 x^4):

-n^4/(3 x^4) - (4 m^7 x^4 y^2)/(3 x^4)

-n^4/(3 x^4) - (4 m^7 x^4 y^2)/(3 x^4) = (-n^4 - 4 m^7 x^4 y^2)/(3 x^4):

Answer: (-n^4 - 4 m^7 x^4 y^2)/(3 x^4)

5 0

2 years ago