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iogann1982 [59]
3 years ago
15

Formula1" title=" \frac{s-1}{4}= \frac{4}{8} 
solve for s" alt=" \frac{s-1}{4}= \frac{4}{8} 
solve for s" align="absmiddle" class="latex-formula">
Mathematics
2 answers:
alex41 [277]3 years ago
7 0
Simplify <span /><span><span><span><span><span><span><span><span><span>4</span><span /></span><span><span>8</span><span /></span><span><span /><span /></span></span></span></span><span /></span></span><span /></span><span>48</span></span> to <span /><span><span><span><span><span><span><span><span><span>1</span><span /></span><span><span>2</span><span /></span><span><span /><span /></span></span></span></span><span /></span></span><span /></span><span>12</span></span>
<span /><span><span><span><span><span><span><span><span><span><span>s</span><span>−</span><span>1</span></span><span /></span><span><span>4</span><span /></span><span><span /><span /></span></span></span><span>=</span><span><span><span><span>1</span><span /></span><span><span>2</span><span /></span><span><span /><span /></span></span></span></span><span /></span></span><span /></span><span>s−14=12</span></span>
2<span> </span>Multiply both sides by <span /><span><span><span><span><span><span>4</span></span><span /></span></span><span /></span><span>4</span></span>
<span /><span><span><span><span><span><span>s</span><span>−</span><span>1</span><span>=</span><span><span><span><span>1</span><span /></span><span><span>2</span><span /></span><span><span /><span /></span></span></span><span>×</span><span>4</span></span><span /></span></span><span /></span><span>s−1=12×4</span></span>
<span> </span>Simplify <span /><span><span><span><span><span><span><span><span><span>1</span><span /></span><span><span>2</span><span /></span><span><span /><span /></span></span></span><span>×</span><span>4</span></span><span /></span></span><span /></span><span>12×4</span></span> to <span /><span><span><span><span><span><span><span><span><span>4</span><span /></span><span><span>2</span><span /></span><span><span /><span /></span></span></span></span><span /></span></span><span /></span><span>42</span></span>
<span /><span><span><span><span><span><span>s</span><span>−</span><span>1</span><span>=</span><span><span><span><span>4</span><span /></span><span><span>2</span><span /></span><span><span /><span /></span></span></span></span><span /></span></span><span /></span><span>s−1=42</span></span>
Simplify <span /><span><span><span><span><span><span><span><span><span>4</span><span /></span><span><span>2</span><span /></span><span><span /><span /></span></span></span></span><span /></span></span><span /></span><span>42</span></span> to <span /><span><span><span><span><span><span>2</span></span><span /></span></span><span /></span><span>2</span></span>
<span /><span><span><span><span><span><span>s</span><span>−</span><span>1</span><span>=</span><span>2</span></span><span /></span></span><span /></span><span>s−1=2</span></span>
Add <span /><span><span><span><span><span><span>1</span></span><span /></span></span><span /></span><span>1</span></span> to both sides
<span /><span><span><span><span><span><span>s</span><span>=</span><span>2</span><span>+</span><span>1</span></span><span /></span></span><span /></span><span>s=2+1</span></span>
Simplify <span /><span><span><span><span><span><span>2</span><span>+</span><span>1</span></span><span /></span></span><span /></span><span>2+1</span></span> to <span /><span><span><span><span><span><span>3</span></span><span /></span></span><span /></span><span>3</span></span>
<span /><span><span><span><span><span><span>s</span><span>=</span><span>3</span></span><span /></span></span><span /></span><span>s=3
</span></span>
ZanzabumX [31]3 years ago
7 0
Hi there, s-1/4-4/8=0. s-1/4-1/2=0. Lastly, s-3/4=0÷+3/4. Therefore, s=3
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Step-by-step explanation:

Assuming that the differential equation is

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First of all, this is an example of the logistic equation, which has the general form

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Notice that this equation is separable, then

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Now, intagrating in both sides of the equation

\int\frac{dP}{P(1-P/K)} = \int kdt = kt +C.

In order to calculate the integral in the left hand side we make a partial fraction decomposition:

\frac{1}{P(1-P/K)} = \frac{1}{P} - \frac{1}{K-P}.

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We have obtained that:

-\ln\left| \frac{K-P}{P}\right| = kt +C

which is equivalent to

\ln\left| \frac{K-P}{P}\right|= -kt -C

Taking exponentials in both hands:

\left| \frac{K-P}{P}\right| = e^{-kt -C}

Hence,

\frac{K-P(t)}{P(t)} = Ae^{-kt}.

The next step is to substitute the given values in the statement of the problem:

\frac{500-P(t)}{P(t)} = Ae^{-0.04t}.

We calculate the value of A using the initial condition P(0)=100, substituting t=0:

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</span>
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